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BigorU [14]
3 years ago
11

Find the GCF of 45 and 75 using the prime factorization. (You can leave your answers in the prime factorization form.)

Mathematics
2 answers:
matrenka [14]3 years ago
8 0

Answer:

15

Step-by-step explanation:

Kisachek [45]3 years ago
7 0

Answer:

<u><em>3*5</em></u>

Step-by-step explanation:

GCF of 45 and 75 = 15

15: 1,3,5,15

3 and 5 are prime numbers so: <u><em>3*5</em></u>=15

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Which of the following inequalities best represents the graph above?
Montano1993 [528]
The inequality n <span>≥ 9 properly represents the graph because the arrow is pointing to the right of 9, and the dot is filled in on 9, representing Greater than or equal to.
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8 0
3 years ago
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A central angle theta in a circle of radius 7 m is subtended by an arc of length 8 m. Find the measure of theta in degrees. (Rou
gogolik [260]

Answer: In degrees , The measure of \theta=65.5^{\circ}

In radians , the measure of  \theta =\dfrac{8}{7}\text{ radians}.

Step-by-step explanation:

We know that the formula for length of arc is given by :-

l=\theta r

, where \theta = Central angle subtended by arc.

r= radius of the circle.

As per given , we have

Radius of circle : r=7 m

Length of arc : l=  8 m

Substitute these values in the above formula , we get

8=\theta (7)\\\\\Rightarrow\ \theta =\dfrac{8}{7}\text{ radians}

Hence, the measure of \theta =\dfrac{8}{7}\text{ radians}.

To convert it into degrees we multiply it with \dfrac{180^{\circ}}{\pi}

The measure of \theta =\dfrac{8}{7}\times\dfrac{180^{\circ}}{\pi}

=(\dfrac{8\times180}{7\times3.14})^{\circ}=65.5141037307^{\circ}

\approx65.5^{\circ}

Hence, the measure of \theta=65.5^{\circ}

8 0
3 years ago
An annual pass to the Super Fun theme
MariettaO [177]

Answer:

Step-by-step explanation:

X=4

7 0
3 years ago
Write an expression that is equivalent to 2/3(4x + 9). (4 points) Select one: a. 8/3x + 6 b. 8/3x + 9 c. 2/3x + 6 d. 2/3x + 9
Lady_Fox [76]
You have to distribute the 2/3 across the equation.

8/3x+18/3 which is 8/3x+6 so the answer is a

I hope that helps
3 0
3 years ago
Newton's law of cooling is:
Mnenie [13.5K]

Answer:

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

Step-by-step explanation:

For this case we have the following differential equationÑ

\frac{du}{dt}= -k (u-T)

We can reorder the expression like this:

\frac{du}{u-T} = -k dt

We can use the substitution w = u-T and dw =du so then we have:

\frac{dw}{w} =-k dt

IF we integrate both sides we got:

ln |w| = -kt +C

If we apply exponential in both sides we got:

w = e^{-kt} *e^c

And if we replace w = u-T we got:

u(t)= T + C_1 e^{-kt}

We can also express the solution in the following terms:

u(t) = (T_i -T_{amb}) e^{kt} +T_{amb}

For this case we know that k =-0.15 hr since w ehave a cooloing, T_{i}= 70 F, T_{amb}=11F, we have this model:

u(t) = (70-11) e^{-0.15t} +11

And if we want that the temperature would be 32F we can solve for t like this:

32 = 59 e^{-0.15 t} +11

21=59 e^{-0.15 t}

\frac{21}{59} = e^{-0.15 t}

If we apply natural logs on both sides we got:

ln (\frac{21}{59}) =-0.15 t

t = \frac{ln(\frac{21}{59})}{-0.15}=6.887 hr

So it would takes approximately 6.9 hours to reach 32 F.

7 0
3 years ago
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