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nikitadnepr [17]
3 years ago
10

There are 32 females cast in the school play. The ratio of male roles is 3:8. How many males are cast in the school play

Mathematics
1 answer:
agasfer [191]3 years ago
3 0
There would be 12 males
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Naddika [18.5K]

Answer:

A: Yes, I agree. Why? Because if you look at the shape, its a triangle right, and a triangle both sides are equal, while the bottom line is not. But because both sides are equal, and half of the triangle is MPN and the other side is QPN, they both are congruent (or equal to)

B: Like I said, both MPN and QPN are both equal, and if you remove the P, it would still be the same because the shape has not changed.

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2 years ago
Melaine charges $4.50 per hour when she washes cars, plus $5.00 for supplies. Which function rule represents the amount y melain
spayn [35]

Answer:

B y= 4.50x + 5.00

Step-by-step explanation:

4.50 is the “mx” in y=mx+b also known as the Slope that moves.

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3 years ago
Write the equation of the line that passes through (−3,1) and (2,−1) in slope-intercept form
Alex787 [66]

Answer:

y=-\frac{2}{5}x-\frac{1}{5}

Step-by-step explanation:

The equation of a line is y = mx + b

Where:

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  • b is the y-intercept

First, let's find what m is, the slope of the line.

Let's call the first point you gave, (-3,1), point #1, so the x and y numbers given will be called x1 and y1.

Also, let's call the second point you gave, (2,-1), point #2, so the x and y numbers here will be called x2 and y2.

Now, just plug the numbers into the formula for m above, like this:

m = -\frac{2}{5}

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-\frac{2}{5}x + b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

  • (-3,1). When x of the line is -3, y of the line must be 1.
  • (2,-1). When x of the line is 2, y of the line must be -1.

Now, look at our line's equation so far: y=-\frac{2}{5}x + b. b is what we want, the --\frac{2}{5} is already set and x and y are just two 'free variables' sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-3,1) and (2,-1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!

You can use either (x,y) point you want. The answer will be the same:

  • (-3,1). y = mx + b or 1=-\frac{2}{5} * -3 + b, or solving for b: b = 1-(-\frac{2}{5})(-3).b = -\frac{1}{5}.
  • (2,-1). y = mx + b or -1=-\frac{2}{5} * 2 + b, or solving for b: b = 1-(-\frac{2}{5})(2). b = -\frac{1}{5}.

See! In both cases, we got the same value for b. And this completes our problem.

The equation of the line that passes through the points  (-3,1) and (2,-1) is y=-\frac{2}{5}x-\frac{1}{5}

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Anni [7]

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Step-by-step explanation:

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