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3 years ago

The sum of two numbers is 18. The quotient of the two numbers is 17. What are the two numbers?

1 answer:

5 0

Let the two numbers be x and y
x + y = 18 . . . . . . . . (1)
x/y = 17 . . . . . . . . (2)
from (2): x = 17y
substituting for x in (1), gives
17y + y = 18
18y = 18
y = 18/18 = 1
x = 17y = 17(1) = 17

Therefore the two numbers are: 1 and 17

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Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

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3 years ago

Find the greatest common factor of 14 and 33.

Paraphin [41]

Answer:

Step-by-step explanation:

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2 years ago

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A toll-free sales line sold 85 products for every 125 calls in one day. What is the daily success rate of the sales line? A. 0.1

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Answer:

C. 0.68

Step-by-step explanation:

Given;

number of products sold in a day by toll-free sales line = 85 products

number of calls in a day = 125

The daily success rate of the sales line is given by the ratio of the total products in a day to total number of calls in a day.

The daily success rate of the sales line = total products sold / number of calls

The daily success rate of the sales line = 85 / 125

The daily success rate of the sales line = 0.68

Therefore, the daily success rate of the sales line is 0.68

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