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Hatshy [7]
4 years ago
5

What are two fractions between 3/5 and 4/5

Mathematics
1 answer:
Elza [17]4 years ago
4 0
6/10 and 13/20, sorry i would explain this but its late, cheers.
Hope this Helps.
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João emprestou R$ 1000,00 a seu amigo José. Para que José conseguisse o empréstimo com o amigo, foram definidas as seguintes con
pochemuha

Answer:

La opción correcta es;

d) R $ 1.200,00

Step-by-step explanation:

El monto que Joao prestó a José = R $ 1.000,00

La duración del préstamo = 6 meses

El plazo de interés del préstamo = interés simple del 10% por trimestre

La cantidad que José tiene que pagarle a Joao después de 6 meses viene dada por la siguiente fórmula de interés simple;

A = P · (1 + r · t)

A = La cantidad que José tiene que pagarle a Joao después de 6 meses

P = La cantidad que Joao prestó a José = R $ 1.000,00

r = La tasa de interés = 10% / trimestre = 10% / (3 meses) = 0.1 / (3 meses)

t = La duración del préstamo = 6 meses

Por lo tanto, al sustituir los valores anteriores en la fórmula de interés simple, tenemos;

A = R $ 1.000,00 × (1 + 0,1 / (3 meses) × 6 meses) = R $ 1.000,00 + R $ 200,00 = $$ 1.200,00

El monto que José debe pagar a Joao después de 6 meses = R $ 1.200,00

8 0
3 years ago
CAN SOMEONE HELP PLZ AND EXPLAIN BEC IF DONT DO GOOD I CANT GO TO MY DADS HOUSE THIS WEEK END
Galina-37 [17]
Hello!

6.
Since the area is that of a square, you know that all side lengths are the same. 

Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².

A = a^{2}
144 = a^{2}
\sqrt{144} = a
12 = a

The length of the side of a square with an area of 144 in² is 12 in.

7.
Rational number.

8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.

Plug in your leg lengths:

a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4
7 0
3 years ago
Can someone please help me with this!! I will award brainliest and 15 points for best answer!!
vekshin1
By using Nathan's expression, Mitchel should have received 2 1/4 pounds of lemon drops. By using Darren's expression, Mitchel should have received  2 1/4 pounds of lemon drops. The difference in the amount of lemon drops Mitchel should have received using Nathan's expression instead of Darren's expression is 0 pounds.
6 0
3 years ago
2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One
Stells [14]

y'=(t+y)^2-1

Substitute u=t+y, so that u'=y', and

u'=u^2-1

which is separable as

\dfrac{u'}{u^2-1}=1

Integrate both sides with respect to t. For the integral on the left, first split into partial fractions:

\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1

\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt

\dfrac12(\ln|u-1|-\ln|u+1|)=t+C

Solve for u:

\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C

\ln\left|1-\dfrac2{u+1}\right|=2t+C

1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}

\dfrac2{u+1}=1-Ce^{2t}

\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}

u=\dfrac2{1-Ce^{2t}}-1

Replace u and solve for y:

t+y=\dfrac2{1-Ce^{2t}}-1

y=\dfrac2{1-Ce^{2t}}-1-t

Now use the given initial condition to solve for C:

y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}

so that the particular solution is

y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}

3 0
3 years ago
a mighty kids meal includes 3.2 ounces of applesauce. If a child eats two frozen meals each week, how many ounces of applesauce
Gelneren [198K]
3.2 + 3.2 = 6.4
6.4 x 52 = 332. 8
Hope it helps!
6 0
3 years ago
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