Answer:
The description of the given scenario is described in the explanation segment below.
Explanation:
- As a charge passes through some kind of potential gap, the electrical task is undertaken as well as energy will be transferred.
- The Potential difference seems to be an amount of work performed per unit charge and is denoted by "V" as well as a charge is denoted by "Q".
<u>The energy transferred could be determined by using the following equation or formula:</u>
⇒ Energy transferred = charge × potential difference
Answer:
2.353 × 10⁵ years
Explanation:
Since speed, v = distance/time
time, t = distance/speed
The distance, d = circumference of orbit = 2πr where r = radius of orbit = 8.5 kiloparsecs = 8.5 kiloparsecs × 3.1 × 10¹³ kilometers/parsec = 26.35 × 10¹³ kilometers and velocity of sun, v = 220 km/s
So, the time it takes to complete one orbit, T is
T = 2πr/v
= 2π × 26.35 × 10¹³ km/220 km/s
= 165.562 × 10¹³ km ÷ 220 km/s
= 0.753 × 10¹³ s
= 7.53 × 10¹² s
We now convert T to years
T = 7.53 × 10¹² s ÷ 3.2 × 10⁷ seconds/year
T = 2.353 × 10⁵ years
Answer:=14,160 kJ
Explanation: Let m1 and m2 be the initial and final amounts of mass within the tank, respectively. The steam properties are listed in the table below
Specific Internal SpecificTemp Pressure Volume Energy Enthalpy Quality Phase
C MPa m^3/kg kJ/kg kJ/kg
1 260 4.689 0.02993 2158 2298 0.7 Liquid Vapor Mixture
2 260 4.689 0.0422 2599 2797 1 Saturated Vapor
The mass initially contained in the tank is m1 = V/v1
m1 =0.85 m^3 /0.02993 m^3 /kg
= 28.4 kg
The mass finally contained in the tank is
m2 =V2/v
= 0.85 m^3 /0.0422 m^3 /kg
= 20.14 kg
The heat transfer is then
Qcv = m2u2 − m1u1 − he(m2 − m1)
Qcv = (20.14)(2599) − (28.4)(2158) − (2797)(20.14 − 28.4) = 14,160 kJ
Answer:
E = 2,575 eV
Explanation:
For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength
E = h f
c = λ f
Where the Planck constant has a value of 6.63 10⁻³⁴ J s
Let's replace
E = h c / λ
Let's calculate for wavelengths
λ = 4.83 10-7 m (blue)
E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷
E = 4.12 10-19 J
The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J
E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
E = 2,575 eV
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