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deff fn [24]
2 years ago
13

A 15 kg block is sliding along a frictionless surface and strikes a 10 kg ball at rest. What is the collision of the blocks afte

r the collision if it is an inelastic collision?
Physics
1 answer:
vfiekz [6]2 years ago
7 0

Answer:

   v = 0.6 v₁

Explanation:

This is an exercise in collisions, let's start by defining a system formed by the two bodies, so that the forces during the collisions have been internal and the momentum is preserved.

Instant starts. Before the crash

       p₀ = M v₁ + m 0

Final moment. After the crash

       p_{f} = (M + m) v

how momentum is conserved

       p₀ = p_{f}

       M v₁ = (M + m) v

       

       v = \frac{M}{M+m} v_{1}

let's calculate

       v = \frac{15}{15+10} v_{1}

        v = 0.6 v₁

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