The bullet will strike the target placed in 324.0 m in the East in 0.45 seconds.
<u>Explanation:</u>
As we all know the epic relation between distance, speed and time; we cam easily estimate the time in which an object can reach to the destination or target.
As here in this case, we know the distance of the target and the velocity of a bullet exerted from a rifle given as follows,
Distance of the Target from the rifle edge = 324.0 m
Velocity of bullet exerted from the rifle = 720 m/s
Since we know that,
or
We can simply implement all the values in the formula and get the results i.e the time required by the bullet to hit the target. Since both the values are in S.I units measures, we don't need to change or convert any of them. Hence,
Therefore, the bullet will hit the target in 0.45 seconds.
Answer:
i think the answer is agility I'm not sure though
Answer:
b.)Electrons leave the negative battery terminal and electrons enter the positive terminal.
Explanation:
- First of all, the carriers of charge in an electrical circuit are the electrons, not the protons. In fact, electrons in a conductor (such as the copper wire) are free to move, while protons are bond inside the nuclei of the atoms, so they are not free to move. This means that only choices a) and b) could be correct.
- Finally, we know that charges with same sign repel each other, while charges with opposite sign attract each other. This means that electrons are repelled by the negative terminal of the battery and attracted by the positive terminal of the battery. Therefore, the correct choice must be
b.)Electrons leave the negative battery terminal and electrons enter the positive terminal.
Answer:
11.3 m/s
Explanation:
First, find the time it takes for the first stone to fall 3.2 m.
Given:
Δy = 3.2 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(3.2 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 0.81 s
Next, find the time for the first stone to land.
Given:
Δy = 15 m
v₀ = 0 m/s
a = 9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
(15 m) = (0 m/s) t + ½ (9.8 m/s²) t²
t = 1.75 s
The difference in time is 1.75 s − 0.81 s = 0.94 s. Find the initial velocity needed for the second stone to land after that amount of time.
Given:
Δy = 15 m
a = 9.8 m/s²
t = 0.94 s
Find: v₀
Δy = v₀ t + ½ at²
(15 m) = v₀ (0.94 s) + ½ (9.8 m/s²) (0.94 s)²
v₀ = 11.3 m/s
Answer:
Quantum theory states that electromagnetic radiation travels in discrete amounts with energy
h ν = E = h c / f
