We have our equation set up for us:
46-46*x=20
move 20 to the other side an then subtract
46*x=26
divide 46 on both sides
x = 26/46
simplify
x=
13/23 which is around
0.56521..
<h2><u><em>
Rounded, the percentage decrease is </em></u></h2><h2><u><em>
</em></u></h2><h2><u><em>
56.5 percent</em></u></h2>
<u><em></em></u>
-Hunter
So a dime is .10 or 10 cents
a quarter is .25 or 25 cents
12(.10)=$1.2
4(.25)=1
the equations would be
.25(x)
.10(x)
and if you need them combined it would be
.25(x) + .10(x)
:)
Answer:
c=face. b=vertex. a=line
Step-by-step explanation:
Answer:
His 95% confidence interval is (0.065, 0.155).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 186, \pi = 0.11](https://tex.z-dn.net/?f=n%20%3D%20186%2C%20%5Cpi%20%3D%200.11)
95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.11%20-%201.96%5Csqrt%7B%5Cfrac%7B0.11%2A0.89%7D%7B186%7D%7D%20%3D%200.065)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.11%20%2B%201.96%5Csqrt%7B%5Cfrac%7B0.11%2A0.89%7D%7B186%7D%7D%20%3D%200.155)
His 95% confidence interval is (0.065, 0.155).