1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
galina1969 [7]
3 years ago
7

Please help! i dont understand

Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

QUESTION 1

The given inequality is  

y\leq x-3 and y\geq -x-2.

If (3,-2) is a solution; then it must satisfy both inequalities.

We put x=3 and y=-2 in to both inequalities.

-2\leq 3-3 and -2\geq -3-2.

-2\leq 0:True and -2\geq -5:True

Both inequalities are satisfied, hence (3,-2) is a solution to the given system of inequality.

QUESTION 2

The given inequality is  

y\:>\:-3x+3 and y\:>\: x+2.

If (1,4) is a solution; then it must satisfy both inequalities.

We put x=1 and y=4 in to both inequalities.

4\:>\:-3(1)+3 and 4\:>\: 1+2.

4\:>\:0:True and 4\:>\: 3:True

Both inequalities are satisfied, hence (1,4) is a solution to the given system of inequality.

Ans: True

QUESTION 3

The given inequality is  

y\leq 3x-6 and y\:>\: -4x+2.

If (0,-2) is a solution; then it must satisfy both inequalities.

We put x=0 and y=-2 in to both inequalities.

-2\leq 3(0)-6 and -2\:>\: -4(0)+2.

-2\leq -6:False and -2\:>\:2:False

Both inequalities are not satisfied, hence (0,-2) is a solution to the given system of inequality.

Ans:False

QUESTION 4

The given inequality is  

2x-y\: and x+y\:>\:-1.

If (0,3) is a solution; then it must satisfy both inequalities.

We put x=0 and y=3 in to both inequalities.

2(0)-3\: and 0+3\:>\:-1.

-3\::True and 3\:>\:-1: True

Both inequalities are satisfied, hence (0,3) is a solution to the given system of inequality.

Ans:True

QUESTION 5

The given system of inequality is  

y\:>\:2x-3 and y\:.

If (-3,0) is a solution; then it must satisfy both inequalities.

We put x=-3 and y=0 in to both inequalities.

0\:>\:2(-3)-3 and 0\:.

0\:>\:-9;True and 0\::True

Both inequalities are satisfied, hence (-3,0) is a solution to the given system of inequality.

Ans:True

You might be interested in
​
DedPeter [7]

Answer:

The solution is (3/8, -7/8).

Step-by-step explanation:

y = −5x + 1

y = 3x − 2

Since  the 2 expressions in x are both equal to y :

−5x + 1  = 3x - 2

-5x - 3x = -2 - 1

-8x = -3

x = 3/8.

So y = 3x - 2

= 3(3/8) - 2

= 9/8 - 2 = -7/8.

6 0
3 years ago
What is the area of the following circle
Alex17521 [72]

Answer:

Area = 153.86

Step-by-step explanation:

Formula: A = \pi r^{2}

diameter (d) = 14

radius = d / 2

radius is 14 / 2 = 7

A = \pi (7)^{2}\\\pi 49\\49\pi \\49(3.14) = 153.86

8 0
1 year ago
you have just win a prize that pays you 1$ for the first day , 2$ on the second day 3$ on the third day and so on for the month
vivado [14]
The answer is $31 dollars because there is 31 days in August
8 0
3 years ago
Read 2 more answers
How many twenty fourths would five sixths equal
borishaifa [10]
5/6     =  x/24

6 times 4 is 24
(you have to times denominator and numerator by the same number)
5 times 4 = 20'
it would be 20/24
7 0
3 years ago
A manufacturing company has two retail outlets. It is known that 30% of all potential customers buy
aleksandrvk [35]

Answer:

(a) A y P(A) = 0.4 (b) \bar{B} y P(\bar{B})=0.5 (c) \bar{A}∪\bar{B} y P(\bar{A}∪\bar{B}) = 0.9 (d) \bar{A}∩\bar{B} y P(\bar{A}∩\bar{B})=0.2

Step-by-step explanation:

A was defined as the event that a potential customer, randomly chosen, buys from outlet 1 in the original problem statement. We know that B denotes the event that a randomly chosen customer buys from outlet 2. So

P(A\cap \bar{B}) = 0.3, P(B\cap \bar{A}) = 0.4 and P(A\cap B) = 0.1

(a) P(A) = P(A\cap (B\cup\bar{B})) = P(A\cap B) + P(A\cap \bar{B}) = 0.1 + 0.3 = 0.4

(b)  P(B) = P(B\cap (A\cup\bar{A})) = P(B\cap A) + P(B\cap \bar{A}) = 0.1 + 0.4 = 0.5

P( \bar{B}) = 1-P(B) = 1-0.5 = 0.5

(c) The customer does not buy from outlet 1 is the complement of A, i.e.,  \bar{A}, and the customer does not buy from outlet 2 is the complement of B, i.e.,  \bar{B}, so, the customer does not buy from outlet 1 or does not buy from outlet 2 is  \bar{A}∪ \bar{B} and P(\bar{A}∪ \bar{B}) = P((A\cap B)^{c}) by De Morgan's laws

P((A\cap B)^{c})  = 1-P(A∩B)=1-0.1=0.9

(d) The customer does not buy from outlet 1 is the complement of A, and the customer does not buy from outlet 2 is the complement of B, so we have that the statement in (d) is equivalent to \bar{A}∩\bar{B} and P( \bar{A}∩\bar{B}) = P((AUB)^{c}) by De Morgan's laws, and

P((AUB)^{c}) = 1-P(A∪B)=1-[P(A)+P(B)-P(A∩B)]=1-[0.4+0.5-0.1]=1-0.8=0.2

8 0
2 years ago
Other questions:
  • Convert to the given unit.<br> 3 T=___lb
    14·1 answer
  • A small water bottle holds of a liter. A
    10·1 answer
  • What part of $40.00 is $15.00​
    5·1 answer
  • In a appropriate environment, guppies reproduce at an astounding rate. A population of reproducing guppies quadruples every mont
    13·1 answer
  • Amber charges $8.25 per hour to baby-sit. One Saturday she baby sat for 3.5 hours in the morning and 2.25 hours in the afternoon
    15·1 answer
  • 2^3 rational or irrational
    7·1 answer
  • FIRST WILL BE MARKED BRAINLIEST!
    15·1 answer
  • Jim sells hot dogs for $2.95 each and steak sandwiches for $9.95 each out of his food cart. During a busy outdoor festival, he s
    14·2 answers
  • 7. Use graph paper to graph each linear function:<br> f(x) = 4x - 7
    10·1 answer
  • Whixh list of numbers is ordered from least to greatest?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!