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3 years ago

Draw the products of benzoic acid reacting with sodium hydroxide.

Chemistry

1 answer:

Katena32 [7]3 years ago

6 0

Answer:

Products: C6H5COO-Na+ (aq) + H2O (l)

Explanation:

when the benzoic acid react with sodium hydroxide, the acid part i.e carboxyl group is react with the base and produce ionic compound sodium benzoate (C6H5COO-Na+).

Chemical equation:

C6H5COOH + NaOH → C6H5COO-Na+ + H2O

Chemical reaction with physical states:

C6H5COOH (s) + NaOH (aq) → C6H5COO-Na+ (aq) + H2O (l)

Sodium benzoate is very polar ionic compound and soluble in water. If we add HCl into this solution sodium benzoate will be converted back into benzoic acid.

Properties of benzoic acid:

1. it is colorless solid.

2. it is crystalline in nature.

3. it is aromatic compound with the formula C7H6O2.

4. it is soluble into benzene, alcohol and ether.

5. its molar mass is 122.12 g/mol.

Properties of sodium benzoate:

1. Sodium benzoate is white odorless chemical compound.

2. It is aromatic compound and molecular formula is C7H5NaO2.

3. Its molecular weight is 144.11 g/mol.

4. it is sweet in taste and soluble in water.

5. it is used as preservative because of its antimicrobial properties.

Properties of Sodium hydroxide:

1. it is colorless solid and inorganic compound.

2. it is crystalline in nature.

3. its molar mass is 40 g/mol.

4. its molecular formula is NaOH.

5. its melting point is 318 °C.

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Answer:

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I hope it helps.

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3 years ago

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1) A box has a mass of 8 kg and a volume of 2 m? What is its density? |

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$\huge\boxed{4\ \text{kg/m$^3$}}$

We know that $\rho=m\div V$ , where $\rho$ is density, $m$ is mass, and $V$ is volume.

Substitute in the values we know and solve:

$\begin{aligned}\rho&=8\div2\\&=\boxed{4}\end{aligned}$

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3 years ago

If an oxygen isotope has 8 protons and 10 neutrons in its nucleus, what is its atomic mass

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4 years ago

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Which of the following aqueous solutions will have the lowest freezing point? a. 0.75 m (NH4)3PO4 b. 1.0 m CaSO4 c. 1.0 m LiCl d

Nataly [62]

Answer: a. 0.75m (NH4)3PO4 will have the lowest freezing point .

Explanation: Freezing point decreases as the concentration of the solute substance increases. Assuming the same solvent for all of them, for instance water.

∆T= i.Kf.b

∆T= freezing point depression

i= vant Hoff factor

Kf= molality

Assuming water to be the solvent for all Kf=1.86°C/M

VANT HOFF FACTORS :

For (NH4)3PO4

This has 3 ionic bonding and 1 covalent bonding making it 4 bond

Therefore i=4

For CaSO4

This has 1 metallic bond and 1 covalent bond making it 2 bond.

Therefore i=2

For LiCl

This has 1 metallic bond and 1 non metallic bond making it 2 bond.

Therefore i=2

For CH3OH

This has only 1 covalent bond.

Therefore i=1

MOLALITY:

(NH4)3PO4 = 0.75M

CaSO4= 1.0M

LiCl= 1.0M

CH3OH= 1.5M

FREEZING POINT DEPRESSION:

For (NH4)3PO4

∆T= 4×0.75×1.86=5.58°C

For CaSO4

∆T= 2×1.0×1.86=3.72°C

For LiCl

∆T = 2×1.0×1.86= 3.72°C

For CH3OH

∆T= 1×1.5×1.86=2.79°C

REMEMBER THE HIGHER THE FREEZING POINT DEPRESSION THE LOWER THE FREEZING POINT.

FREEZING POINT DEPRESSION IS THE CHANGE IN THE FREEZING POINT PROPORTIONAL TO THE AMOUNT OF SOLUTE ADDED THE THE SOLUTION.

THEREFORE THE ONE WITH THE LOWEST FREEZING POINT IS (NH4)3PO4

4 0

4 years ago

Would silver react with dilute sulfuric acid?why or why not?

soldi70 [24.7K]

No, Silver will not react with dilute sulfuric acid.

<u>Explanation:</u>

As Silver has the least reactivity, it is not capable to reduce hydrogen ion from sulfuric acid, even when the acid is in concentrated state. But if the concentrated acids are heated then the Silver may form Ag+ ions.

But silver (Ag) can react with the hot concentrated sulfuric acids ( $H_{2} S O_{4}$ ). As mentioned in below to equation.

$2 A g+2 H_{2} S O_{4} \rightarrow A g_{2} S O+2 H_{2} O$

So if dilute sulfuric acid is used then there will not be any kind of reaction with silver ions.

4 0

3 years ago