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agasfer [191]
3 years ago
7

36g of an alloy of copper and zinc contains 45% copper. how much pure copper do you need to add in order to get a 60% copper all

oy?

Chemistry
1 answer:
iogann1982 [59]3 years ago
7 0
First, you need to count copper mass in alloy.
Second, you have to make an equation an find x ( the copper mass must be added). The answer is: 13,5g pure copper

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Write the net ionic equation for the precipitation of cobalt(ii) carbonate from aqueous solution
andrey2020 [161]
Missing question: Write the net ionic equation for the precipitation reaction that occurs when aqueous solutions of ammonium carbonate and cobalt(II) bromide are combined.<span>Balanced chemical reaction:
(NH</span>₄)₂CO₃(aq) + CoBr₂(aq) → CoCO₃(s) + 2NH₄Br(aq).
Net ionic reaction:
2NH₄⁺(aq) + CO²⁻(aq) + Co²⁺(aq) + 2Br⁻(aq) → CoCO₃ + 2NH₄(aq)+ 2Br(aq).
or CO²⁻(aq) + Co²⁺(aq) → CoCO₃(s).
4 0
3 years ago
What is the volume of 0.20 moles of helium at STP?
stealth61 [152]

The volume of 0.20 moles of helium at STP is 4.5 liters.

Explanation:

Given:

Number of moles  = 0.20 moles

To Find:

The volume of Helium at STP =?

Solution:

According to ideal gas law

PV = nRT

where

P is pressure,  

V  is volume,  

n  is the number of moles  

R  is the gas constant, and  

T  is temperature in Kelvin.

The question already gives us the values for  p  and  T ,because helium is at STP. This means that temperature is  273.15 K  and pressure is  1 atm .

We also already know the gas constant. In our case, we'll use the value of  

0.08206 L atm/K mol  since these units fit the units of our given values the best

On substituting these values we get

1 atm \times  V = 0.20 moles  \times  0.08206 L atm/K mol

V = \frac{0.20 moles  \times  0.08206 L atm/K mol }{ 1 atm}

V = \frac{4.482}{1}

V =  4.5 Liters

7 0
3 years ago
Hydrogen peroxide can decompose to water and oxygen by the following reaction
mestny [16]
To begin calculating, there is one thing you need to remember :1 mole of H2O2=34.0148 g
Then we have 5.00g of H2O2=5/34.0148=0.146995
As you know decomposition of 2moles now has prodused <span>196kj
So, </span><span>q is made due </span>0.146995 moles of H2O2=(-196/2)*0.146995=-14.40551Kj
I'm sure it will help.
6 0
2 years ago
The MSDS for benzene indicates that it is a clear liquid that has a substantial vapor pressure. It has a health rating of 2, a f
sattari [20]

Answer:

Benzene must be kept away from flames.

Explanation:

Edge2020

6 0
3 years ago
Read 2 more answers
Please help thank you
maxonik [38]

Answer:

K=1.7x10^{-3}

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:

K=\frac{[NO]^2}{[N_2][O_2]}

Next, we plug in the given concentrations on the data table to obtain:

K=\frac{(0.034)^2}{(0.69)(0.98)}\\\\K=1.7x10^{-3}

Regards!

5 0
2 years ago
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