A sample consisting of various gases contains 3.2×10−6 mole fraction of radon. This gas at a total pressure of 34 atm is shaken
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Answer:
The volume of the 50% solution used is 0.8 gallons and the volume of 25% solution used is 1.2 gallons.
Explanation:
Let the volume of the 50% solution be be x gallons.
Let the volume of 25% solution be y gallons.
Total volume of the solution after mixing above volumes of the solutions = 2 gallons
x gal + y gal = 2 gal
...[1]
Percentage of the final salt solution = 35%
....[2]
On solving [1] and [2] , we get:
x = 0.8 , y = 1.2
So, the volume of the 50% solution used is 0.8 gallons and the volume of 25% solution used is 1.2 gallons.