Answer:
The molar concentration of radon is 4.38 x 10⁻⁶ mol.L⁻¹
Explanation:
Molar fraction = number of moles of a certain component / total number of moles
Partial pressure = Total pressure x molar fraction
Partial pressure = 34 atm x 3.2 x 10⁻⁶
Partial pressure = 1.09 x 10⁻⁴ atm
Considering radon as an ideal gas, PV = nRT
molar concentration = n/V
n/V = P/RT
n/V = 1.09 x 10⁻⁴ atm / 0.082 L.atm.mol⁻¹K⁻¹ x 303.15K
n/V = 4.38 x 10⁻⁶ mol.L⁻¹