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2 years ago

Find the value of m: 4(m+4)=40WILL MARK BRAINLIEST!

Mathematics

2 answers:

Bad White [126]2 years ago

8 0

Answer:

m=6

Step-by-step explanation:

4(m+4)=40

m+4=10

m=6

Mrac [35]2 years ago

5 0

Answer:

m=6

Step-by-step explanation:

1.) first we will need to use distributive property and eliminate the parentheses. so multiply 4 by everything inside the parentheses: 4m + 16 = 40.

2.) Next we will have to subtract 16 from both sides: 4m + 16 = 40

-16 -16

and then the 16 would be gone, so you're left with 40 - 16 which is equivalent to 24

3.) now our equation looks like 4m = 24, our final step is to get (m) alone, so using inverse operations. the inverse of multiplication is division so then you'd need to divide both sides by 4:

4m = 24

__ ___ 24 divided by 4 equals 6.

4 4 so m=6.

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a baseball helmet cost $42 coach Rodger said he would pay $274 for 7 helmets is the exact answer reasonable

Zepler [3.9K]

No cause if I helmet cost $42 , 7 helmets will be $294.
$42 = 1 helmet
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3 years ago

7.003 x 10 to the power of 4

pishuonlain [190]

In scientific notation, just move the decimal point over however many numbers are in the power.

In 7.003 • 10^4, move the decimal point over 4 places to the right, (or left if it's negative) making it 70,030

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3 years ago

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the lowest temperature ever recorded on earth's surface was −128.5°f. the highest temperature was 262.5°f higher than the lowest

vlabodo [156]

Answer: 134 °f

Step-by-step explanation:

Lowest is -128.5 °f, the highest is 262.5 °f higher than the lowest.

you would simply add 262.5 °f to your -128.5 °f, giving you 134 °f.

another way of doing this is subtracting 128.5 from 262.6

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2 years ago

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Which calculation can be used to find the value of q in the equation q3 = 64?

alexandr402 [8]

To isolate the variable q, divide both sides by 3:
q3 ÷ 3 = 64 ÷ 3
q = 21.33 or 21 1/3

If the q is cubed(I can't really tell), however, you would use the cube root:
³√q³ = ³√64
q = 4

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2 years ago

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Could the inverse of a non-function be a function? Explain or give an example.

Kitty [74]

Answer:

The inverse of a non-function mapping is not necessarily a function.

For example, the inverse of the non-function mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is the same as itself (and thus isn't a function, either.)

Step-by-step explanation:

A mapping is a set of pairs of the form $(a,\, b)$ . The first entry of each pair is the value of the input. The second entry of the pair would be the value of the output.

A mapping is a function if and only if for each possible input value $x$ , at most one of the distinct pairs includes $x\!$ as the value of first entry.

For example, the mapping $\lbrace (0,\, 0),\, (1,\, 0) \rbrace$ is a function. However, the mapping $\lbrace (0,\, 0),\, (1,\, 0),\, (1,\, 1) \rbrace$ isn't a function since more than one of the distinct pairs in this mapping include $1$ as the value of the first entry.

The inverse of a mapping is obtained by interchanging the two entries of each of the pairs. For example, the inverse of the mapping $\lbrace (a_{1},\, b_{1}),\, (a_{2},\, b_{2})\rbrace$ is the mapping $\lbrace (b_{1},\, a_{1}),\, (b_{2},\, a_{2})\rbrace$ .

Consider mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ . This mapping isn't a function since the input value $0$ is the first entry of more than one of the pairs.

Invert $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ as follows:

$(0,\, 0)$ becomes $(0,\, 0)$ .
$(0,\, 1)$ becomes $(1,\, 0)$ .
$(1,\, 0)$ becomes $(0,\, 1)$ .
$(1,\, 1)$ becomes $(1,\, 1)$ .

In other words, the inverse of the mapping $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ would be $\lbrace (0,\, 0),\, (1,\, 0),\, (0,\, 1),\, (1,\, 1) \rbrace\!$ , which is the same as the original mapping. (Mappings are sets. There is no order between entries within a mapping.)

Thus, $\lbrace (0,\, 0),\, (0,\, 1),\, (1,\, 0),\, (1,\, 1) \rbrace\!$ is an example of a non-function mapping that is still not a function.

More generally, the inverse of non-trivial ellipses (a class of continuous non-function $\mathbb{R} \to \mathbb{R}$ mappings, including circles) are also non-function mappings.

3 0

2 years ago