The square footage of the path is 47.1 ft²
The area of a circle is:
A = πr²
Where r is the radius of the circle.
Let us assume that the pool is a circle.
Given that the pool has a radius (r₁) of 7 feet and a path 1 foot wide would go round the pool.
Radius of pool and cement path (r₂) = 7 ft + 1 ft = 8 ft.
The square footage of the path = πr₂² - πr₁² = π*8² - π * 7² = 47.1 ft²
Hence The square footage of the path is 47.1 ft²
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Answer:
We conclude that option A is true as x = 1 is the root of the polynomial.
Step-by-step explanation:
Given the polynomial

Let us determine the root of the polynomial shown below.


switch sides

as

so the equation becomes

Using the zero factor principle

solving




and


The possible roots of the polynomial will be:

Therefore, from the mentioned options, we conclude that option A is true as x = 1 is the root of the polynomial.
Convert 7.7% to a decimal then multiply by 280 to get your answer
The answer is C because If it is 2 cm=6 ft then, 3*6=18 and 4*6=24.
Do the area of the triangle and then the square