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yarga [219]
4 years ago
13

Please help me ASAP, i will give a thanks and rate you 5 stars. Review the surface area and volume formulas for the following fi

gures:
cone, cylinder, cube, pyramid, rectangular prism, sphere, triangular prism.
Think about the relationship between the surface area and volume of each shape. What are the pros and cons of each shape from a packaging design standpoint. Which figure will you chose for your cereal box design? Write down the formulas for the surface area and volume of this figure and explain why you choose it. You will turn in the following: a paragraph discussing the figure you will use for your packaging design, including the name of the figure you choose, the formula for its surface area, the formula for its surface volume and the reasons why you believe it is the best figure for your cereal box. This is for Unit 6 lesson 8 for people who go to Connexus Academy, who will know what i am needing help on.
Mathematics
1 answer:
PtichkaEL [24]4 years ago
6 0
I think the best figure for a cereal box would be a cylinder. There are no corners on a cylinder where it is hard to fit round pieces of cereal into.  The formula for the surface area of the cylinder is 2*pi*r*h+2*pi*r^2. The formula for the volume of the cylinder is pi*r^2*h. (Then I would add some more info supporting why you think a cylinder would make a good box.)
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Solve the following equation and determine if it has one solution, no solution, or infinitely many solutions: 3x+1−3(x−1)=4
vaieri [72.5K]

Answer:

1/3  , only one solution

Step-by-step explanation:

3x-1 = 1-3x

3x-1 = -3x+1

6x-1 = 1

6x = 2

x = 1/3

7 0
3 years ago
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A researcher is testing a new painkiller that claims to relieve pain in less than 15 minutes, on average.a.State the hypotheses
Ivenika [448]

Answer:

I have a feeling it won't be exactly 15 minutes but it'll be around that time, if it's true.

Step-by-step explanation:

4 0
3 years ago
Suppose you cut a square into two identical triangles what type of triangles will you make
Basile [38]

Answer:

Right angled isosceles triangle.

Step-by-step explanation:

To cut a square into identical triangle one  need   to draw a diagonal for the square.

Suppose ABCD is the square then AC is one diagonal.

The two triangles will be

ABC and ADC

ABC has sides AB , BC and AC

ADC has sides AD, DC, AC

Since ABCD is a square its sides AB, BC , CD , DA are equal hence

for triangle ABC and ADC

side AB , BC and AD, DC will be equal

also AC is common side hence third side of both triangle is also equal .

Hence  ABC and ADC are identical triangle.

___________________________________________

for  triangle ABC

two sides are same in length and third is different

for triangle ABC,  AB =  BC but AC is not equal to AB and AC

and angle ABC is right angled as it angle of square

As two sides are equal and one angle is right angled  

hence triangle ABC is right angled isosceles triangle

_______________________________________

for  triangle ADC

two sides are same in length and third is different

for triangle ADC,  AD= DC  but AC is not equal to AD and DC

and angle ADC is right angled as it angle of square

As two sides are equal and one angle is right angled

therefore triangle ADC is right angled isosceles triangle

_________________________________________________

To understand the solution we need to draw square ABCD and diagonal AC to have better visual understanding of solution.

4 0
4 years ago
One number is 6 more than another. Their sum is 42. Find the two numbers
Triss [41]
18 and 24 are the two numbers.
8 0
3 years ago
How to solve for first derivative?? I have two questions, one where I have the answer, however one where I don’t. The format of
rjkz [21]

Answer:

Q1: f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

Q2: f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

Step-by-step explanation:

The derivative of the product of two functions is:

f(x) = v(x)u(x)

f'(x) = v(x)u'(x) + u(x)v'x)

The derivative is the product of the first function and the derivative of the second function added to the product of the second function and the derivative of the first function.

Q1: The function you are given is:

f(x) = 6x^8(-6x^8 + 2x^4 + 4)

You can think of that function as the product of functions

u(x) = 6x^8 and v(x) = -6x^8 + 2x^4 + 4

We first find the derivatives of functions u and v:

u'(x) = 48x^7 and v'(x) = -48x^7 + 8x^3

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^8)(-48x^7 + 8x^3) + (-6x^8 + 2x^4 + 4)(48x^7)

Use the commutative property to change the order of the sum.

f'(x) = (-6x^8 + 2x^4 + 4)(48x^7) + (6x^8)(-48x^7 + 8x^3)

This is the solution you have.

Q2: The function you are given is:

f(x) = 6x^4(6x^3 - 6x^9 + 3)

You can think of that function as the product of functions

u(x) = 6x^4 and v(x) = 6x^3 - 6x^9 + 3

We first find the derivatives of functions u and v:

u'(x) = 24x^3 and v'(x) = 18x^2 - 54x^8

Now we follow the rule above:

f'(x) = v(x)u'(x) + u(x)v'x)

f'(x) = (6x^4)(18x^2 - 54x^8) + (6x^3 - 6x^9 + 3)(24x^3)

5 0
3 years ago
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