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3 years ago

8 (6× + 5) + 2× equivalent

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

8(6x + 5) + 2x
8(6x) + 8(5) + 2x
48x + 40 + 2x
50x + 40

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Match the parametric equations with the verbal descriptions of the surfaces by putting the letter of the verbal description to t

alukav5142 [94]

Answer:

1. B

2. C

3. A

4. D

Step-by-step explanation:

The parametric equations of the circular cylinder are:

$x(u,v)=a\cos v\\y(u,v)=a\sin v\\z(u,v)=u$

If the orientation of the cylinder is changed to have the height $u$ along the x-axis, the parametric equations of the cylinder match:

$3. \mathbf{r} \left( u, v \right) = u \mathbf{i} + \cos v \mathbf{j} + \sin v \mathbf{k}$

The parametric equations of the circular paraboloid are:

$x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=u^2$

Using the units vectors the parametric equations match:

$1. \mathbf{r} \left( u, v \right) = u \cos v \mathbf{i} + u \sin v \mathbf{j} + u^{2} \mathbf{k}$

The parametric equations of the cone are:

$x(u,v)=au\cos v\\y(u,v)=au\sin v\\z(u,v)=u$

Using the units vectors and rotating the base of the cone from $z=0$ to $x=0$ the parametric equations match:

$2. \mathbf{r} \left( u, v \right) = u \mathbf{i} + u \cos v \mathbf{j} + u \sin v \mathbf{k}$

The equation left is the equation of a plane:

$4. \mathbf{r} \left( u, v \right) = u \mathbf{i} + v \mathbf{j} + \left( 2u - 3v \right) \mathbf{k}$

5 0

3 years ago

What is 1/2 of 7/8? In fraction firm

dimulka [17.4K]

1/2*7/8=7/16

Answer:

7/16

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3 years ago

The intersection of any two disjoint sets is a null set. Justify your answer.

Ne4ueva [31]

Answer:

Yes The intersection of any two disjoint sets is a null set

if two sets do not have any common element then their intersection does not have any element Therefore its intersection is a null set

Step-by-step explanation:

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3 years ago

Find the difference of 6/7 minus 1/14

VMariaS [17]

Answer:

11/14

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

student tickets for the football game cost $12 each and adult ticket cost $20 $1,720 was collected for the 120 ticket sold at la

erik [133]

Answer:

85 student tickets and 35 adult tickets were sold.

Step-by-step explanation:

Howdy!

We know that student tickets cost $12, adult ticket cost $20 and 120 tickets were sold.

So:

$12×A + $20×B = $1,720. Where A and B are the number of student tickets and adult tickets sold, respectively.

Given that 120 tickets were sold in total, we have that:

A + B = 120

So the system of equations to be solved is the following:

$12×A + $20×B = $1,720 (1)

A + B = 120 (2)

Solving for 'A' in equation (2) we get:

A = 120 - B

Substituting this value into equation (1) we get:

$12×(120 - B) + $20×B = $1,720

Solving for 'B' we have:

$12×(120 - B) + $20×B = $1,720

$1,440 - $12×B + $20×B = $1,720

$1,440 + $8×B = $1,720

$8×B = $1,720 - $1,440

$8×B = $280

B = 35 tickets.

Given that B = 35, then A = 120 - 35 = 85 tickets.

So 85 student tickets and 35 adult tickets were sold.

4 0

3 years ago

Read 2 more answers