The real solutions are {

}.
The imaginary solutions are {

}.
Answer:
The slope of the line is 19
Step-by-step explanation:
slope=(y2-y1)/(x2-x1)=(27-(-30))/(39-36)=57/3=19
Therefore, the slope of the line is 19
Answer:
2002 pounds
Explanation:
To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.
This equation can be founded using the following

Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:

Now, we can solve for y

Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above
y = 6x + 1900
y = 6(17) + 1900
y = 102 + 1900
y = 2002
Therefore, the answer is 2002 pounds
Answer:
Quotient means the result of division. To use guess and check to solve, you would divide different numbers by 7 until you get 9. The result is 63 ÷ 7 = 9. The quotient of sixty-three and seven is nine.
Step-by-step explanation:
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