The answer to this is B. 8/5 pounds.
8 pounds divided into 5 piles=1.6 or 8/5
Answer:
301.57
Step-by-step explanation:
I think this is it. I divided the total before taxes by the percentage and added what I got from the division to the total before taxes.
The proportion of defective corks produced by this machine through z test comes out is 0.320.
Given mean of 2 cm and standard deviation of 0.1 cm, The diameter is between 1.9 and 2.1 cm.
We have to find the proportion of defective corks that are produced by machine.
In this problem we have to first find z score and then we will be able to find the probability of defective corks produced by the machine.
Z=(X-μ)/σ
μ=2 cm and σ=0.1 cm.
Z value corresponding to X=1.9.
Z=(1.9-2)/0.1
=-0.1/0.1
=-1
Z value corresponding to X=2.1.
Z=(2.1-2)/0.1
=0.1/0.1
=1
P value of P(-1<Z<1)=2*0.3410=0.6820
Proportion of corks which are not defective=0.6820.
Proportion of corks which are defective=1-0.680.
=0.320
Hence the proportion of defective corks produced by machine is 0.320.
Learn more about z test at brainly.com/question/14453510
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Answer:
1,500 tickets in total (375 adult tickets and 1,125 children tickets)
Step-by-step explanation:
Let x be the number of adult tickets sold.
Three times as many children tickets were sold as adults, so 3x is the number of children tickets sold.
Children tickets were three dollars, so 3x children tickets cost 
Adult tickets were seven dollar, so x adult tickets cost 
The school sold $6000 worth of tickets.
Hence,
