Log_(10)(x² - 4x + 7) = 2
Take the base 10 anti log of both sides.
x² - 4x + 7 = 10² = 100
x²- 4x - 93 = 0
Quadratic Formula
x = [4 ± √(4²-4(1)(-93))]/[2(1)] = [4 ± 2√97)]/2 = 2 ± √97
15%?
Its 15 because it just is because I am big brain.
Its the thingy because 5 and 5 and another 5 plus 1500 = 15%
No idea how I came up with 15%
The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound
<h3>Data obtained from the question</h3>
From the question given above, the following data were obtained:
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Work done (Wd) =?
<h3>How to determine the spring constant</h3>
- Force (F) = 3 pounds
- Extension (e) = 0.6 feet
- Spring constant (K) =?
F = Ke
Divide both sides by e
K = F/ e
K = 3 / 0.6
K = 5 pound/foot
Thus, the spring constant of the spring is 5 pound/foot
<h3>How to determine the work done</h3>
- Spring constant (K) = 5 pound/foot
- Extention (e) = 0.7 feet
- Work done (Wd) =?
Wd = ½Ke²
Wd = ½ × 5 × 0.7²
Wd = 2.5 × 0.49
Wd = 1.23 foot-pound
Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound
Learn more about spring constant:
brainly.com/question/9199238
#SPJ1
I can’t see your picture what do it say?
