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s2008m [1.1K]
3 years ago
7

If speed is constant but the time of travel ends up being less, what must have

Physics
1 answer:
Vika [28.1K]3 years ago
3 0

Answer:

Distance traveled must have <u>decreased.</u>

Explanation:

Distance is defined as the product of speed of a body and the total time taken to cover that given distance.

If distance traveled is 'd', speed is 's' and time of travel is 't, then:

d=st

From the above equation, it is clear that, distance is directly proportional to the speed as well as the time of travel.

Here, in the question, speed is constant and the time of travel is reduced. So, from the above relation, we can conclude that distance will also decrease if the speed is constant as distance is directly proportional to the time of travel.

Hence, if the time of travel ends up being less, the distance covered must have decreased for speed being constant.

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What is the magnitude of speed of a person goes 75 meters east followed by 20 meters west in 4 seconds
marshall27 [118]

Answer:23.75 m/sec

Explanation:

Total distance is 75+20=95m

Speed is =95/4

23.75 m/s

4 0
3 years ago
Which of the following is a characteristic of active transport? Check all answers that apply.
vlada-n [284]
B. It moves substances against a concentration gradient. It requires energy from the cell to.

Hope this helps :)
5 0
4 years ago
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True or false? a Movable pulley does not provide mechanical advantage.<br><br>False<br><br>True
shepuryov [24]

Answer:

i think its false i hope u get it correct

4 0
3 years ago
a block is pushed up a frictionless 40 incline. if the initial velocity after the push is 5.00 m/s. how far along the incline do
Lana71 [14]

Answer:

d=1.982m, t=1.019s

Explanation:

There are different approaches we can take to solve this problem. You could either solve this by using conservation of energy or by taking a kinematic approach. I'll solve this by using kinematics. So, the very first thing we need to do in order to solve this is do a drawing of the situation so we can analyze it better. (See attached picture).

So, since we are talking about an inclined plane, we can see that the force of gravity is being split into an x and y components if we incline the axis of coordinates. Taking this into account we can see that:

\sum F_{x}=ma_{x}

Since there is no friction in our system, then the only force acting upon the box is the force of gravity, or weight. Since we are taking the upwards direction as the positive direction of movement, we can say that the force of gravity is excerting a negative influence on our box, so this acceleration will be negative, so our sum of forces will now look like this:

-mg sin(40^{o})=ma

we can cancel the masses out so we can see that:

a=-g sin(40°)

a=-9.81m/s^{2} sin(40^{o})

We have now enough information to solve our problem.

we can take the following equation to find the distance the block travels up the incline:

x=\frac{V_{f}^{2}-V_{0}^{2}}{2a}

we know the final velocity must be zero, so we can use the provided data to solve our formula:

x=\frac{(0)^{2}-(5m/s)^{2}}{2(-9.81m/s^{2})sin 40^{o}}

which yields:

x=1.982m

In order to find the time it takes for the block to return to its original position we can use the following formula:

x=V_{0}t+\frac{1}{2}at^{2}

since x=0 is the starting point we can use that to solve our equation:

0=5t+\frac{1}{2}(-9.81sin 40^{o})t^{2}

which simplifies to:

0=5t-4.905t^{2}

which can now be solved for t

t(5-4.905t)=0

t=0                and          5-4.905t=0

t=0                 and         t=\frac{5}{4.905}=1.019

so the time it takes the block to return to its original position is

t= 1.019s

6 0
3 years ago
A man walks 400 m in the direction 45° north of east. Represent this vector graphically by
Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = \frac{length on drawing}{original length}

         = \frac{10}{400}

         = \frac{1}{40}

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is 45^{o} north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0
3 years ago
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