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3 years ago

If speed is constant but the time of travel ends up being less, what must have

Physics

1 answer:

Vika [28.1K]3 years ago

3 0

Answer:

Distance traveled must have decreased.

Explanation:

Distance is defined as the product of speed of a body and the total time taken to cover that given distance.

If distance traveled is 'd', speed is 's' and time of travel is 't, then:

$d=st$

From the above equation, it is clear that, distance is directly proportional to the speed as well as the time of travel.

Here, in the question, speed is constant and the time of travel is reduced. So, from the above relation, we can conclude that distance will also decrease if the speed is constant as distance is directly proportional to the time of travel.

Hence, if the time of travel ends up being less, the distance covered must have decreased for speed being constant.

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Answer:

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Explanation:

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Substituting,

$u_y = (21.5) sin 33.5^{\circ} =11.9 m/s$

The vertical position of the ball at time t is given by

$y = h + u_y t + \frac{1}{2}gt^2$

where

h = 13.5 m is the initial heigth

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The ball reaches the water when y = 0, so

$0 = h + u_yt +\frac{1}{2}gt^2\\0 = 13.5 +11.9 t - 4.9t^2$

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The horizontal velocity of the ball is

$u_y = u cos \theta = (21.5) cos 33.5^{\circ} =17.9 m/s$

And since the motion along the horizontal direction is a uniform motion, we can find the horizontal distance travelled by the ball as follows:

$d= u_x t = (17.9)(3.27)=58.5 m$

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