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vladimir1956 [14]
3 years ago
15

You drive your car for 2.0 h at 40.0 km/h then for 2.0 h at 60.0 km/h what is your average velocity?

Physics
1 answer:
Verdich [7]3 years ago
7 0
In order to calculate velocity, we'd need to know the straight-line distance between the start and the finish, and we'd also need the direction of that line.  The best we can do with the information given in the question is calculate the average SPEED.

Average speed = (total distance covered) / (time to cover the distance).

Distance covered in the first 2 hours = (2 hr) x (40 km/hr) = 80 km.
Distance covered in the second 2 hours = (2 hr) x (60 km/hr) = 120 km.

Total distance covered = (80 + 120) = 200 km
Time to cover the distance = (2 + 2) = 4 hours

Average speed = (200 km) / (4 hours)  =  50 km/hour
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A car stops with an acceleration of -20 m/s/s in 8 seconds. How far did it go while stopping?
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Answer:

640 m.

Explanation:

The following data were obtained from the question:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Distance (s) =.?

Next, we shall determine the initial velocity (u) of the car. This can be obtained as follow:

Acceleration (a) = –20 m/s/s

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u)

a = (v – u) / t

–20 = (0 – u) / 8

–20 = – u / 8

Cross multiply

–20 × 8 = – u

– 160 = – u

Divide both side by – 1

u = – 160 / – 1

u = 160 m/s

Finally, we shall determine the distance travelled by the car before stopping as follow:

Time (t) = 8 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 160 m/s

Distance (s) =.?

s = (v + u)t /2

s = (0 + 160) × 8 /2

s = (160 × 8) /2

s = 1280 / 2

s = 640 m

Therefore, the car travelled 640 m before stopping.

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