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Vsevolod [243]
3 years ago
15

Use the diagram of the solution and its key to answer the questions. What type of solution is represented by the beaker? Which w

ould be a good estimate of the solution’s pH? If you poured out half the solution in the beaker, the pH of the remaining solution would .
Physics
2 answers:
Arisa [49]3 years ago
7 0

Answer:

The answer would: Acidic, pH= 6, stay the same

liberstina [14]3 years ago
4 0

<h2><u>PLEASE MARK BRAINLIEST!</u></h2>

<u></u>

Answer:

On edg2020, quizlet, and brainly, your answers are:

Explanation:

  1. Acidic
  2. pH = 6
  3. Stay the same

I hope this helps you!

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Determine the normal boiling point of a substance whose vapor pressure is 55.1 mm hg at 35°c and has a δhvap of 32 .1 kj/mol. de
atroni [7]
Classius claperyon equation
In (P2/ P2) = ΔHvap/R) × (1/T2-1/T1)
T2 occurs at normal boiling when vapor pressure P2 = 1 atm.
P1 = 55.1 mmHg, P2 = 1 atm = 760mmHg
T1 = 35°c = 308.15k, T2 =
ΔHvap = 32.1kJ/mol = 32100 J/mol
In (760/55.1) = (-32100/ 8.314) × ( 1/T2 - 1/308.15)
The normal boiling point T2 = 390k = 117°c
5 0
4 years ago
A child goes down slide starting from rest if the length of the slide is to him and it takes a child three seconds to go down th
AlexFokin [52]

Answer:

I. dont. know. sorry. I. need. points

4 0
4 years ago
FITT Principle overdue test questions for PE/Wellness. I get two chances and the highest score is the attempt that will be recor
adoni [48]

Answer: The las option

Explanation:

it is the last option because the FITT principal stands for frequency

7 0
3 years ago
Read 2 more answers
A 2.0-kg object moving 5.0 m/s collides with and sticks to an 8.0-kg object initially at rest. Determine the kinetic energy lost
densk [106]

Answer:

20J

Explanation:

In a collision, whether elastic or inelastic, momentum is always conserved. Therefore, using the principle of conservation of momentum we can first get the final velocity of the two bodies after collision. This is given by;

m₁u₁ + m₂u₂ = (m₁ + m₂)v          ---------------(i)

Where;

m₁ and m₂ are the masses of first and second objects respectively

u₁ and u₂ are the initial velocities of the first and second objects respectively

v  is the final velocity of the two objects after collision;

From the question;

m₁ = 2.0kg

m₂ = 8.0kg

u₁ = 5.0m/s

u₂ = 0        (since the object is initially at rest)

<em>Substitute these values into equation (i) as follows;</em>

(2.0 x 5.0) + (8.0 x 0) = (2.0 + 8.0)v

(10.0) + (0) = (10.0)v

10.0 = 10.0v

v = 1m/s

The two bodies stick together and move off with a velocity of 1m/s after collision.

The kinetic energy(KE₁) of the objects before collision is given by

KE₁ = \frac{1}{2}m₁u₁² +  \frac{1}{2}m₂u₂²       ---------------(ii)

Substitute the appropriate values into equation (ii)

KE₁ = (\frac{1}{2} x 2.0 x 5.0²) +  (\frac{1}{2} x 8.0 x 0²)

KE₁ = 25.0J

Also, the kinetic energy(KE₂) of the objects after collision is given by

KE₂ = \frac{1}{2}(m₁ + m₂)v²      ---------------(iii)

Substitute the appropriate values into equation (iii)

KE₂ = \frac{1}{2} ( 2.0 + 8.0) x 1²

KE₂ = 5J

The kinetic energy lost (K) by the system is therefore the difference between the kinetic energy before collision and kinetic energy after collision

K = KE₂ - KE₁

K = 5 - 25

K = -20J

The negative sign shows that energy was lost. The kinetic energy lost by the system is 20J

3 0
4 years ago
Another unfortunate bug splatters on the windshield of a moving car. Which has the greater change in momentum---the bug or the c
bija089 [108]

Answer:

The change in momentum for the bug and the car will be equal, impulses will be equal in opposite directions and the bug will have a greater acceleration compared to the car, because it has a smaller mass.

Explanation:

Hope this helps..

4 0
3 years ago
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