The velocity after 30s would be 38. 99 m/s
<h3>How to calculate the velocity</h3>
Using the formula
F = m Δ V/ t
Where, F = force = 76. 7N
m = mass = 7. 25kg
Δv = change in velocity= V2 - V1 and V1 = 2. 25 m/s
t = time = 3. 50s
76. 7 = 7. 25 × (v2 - 2. 25) / 3. 50
76. 7 = 2. 07 × (v2 - 2. 25)
make v2 subject of formula
v2 - 2. 25 = 76. 07 ÷ 2. 07
v2 = 36. 74 + 2. 25
v2 = 38. 99 m/s
Thus, the velocity after 3. 50s would be 38. 99 m/s
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Answer:
The frequency of the sound note as heard = 429 Hz
Explanation:
The frequency of sound waves as heard from a distance for a sound wave coming towards one at v₀ m/s and whose real frequency is f₀ is given by
+f = f₀/[1 - (v₀/v)]
+f = frequency of sound as heard from the distance away = ?
f₀ = real frequency of sound = 401 Hz
v₀ = velocity at which the sound source is moving towards the reference point = 23.0 m/s
v = velocity of sound waves = 343 m/s
+f = 401/[1 - (23/343)]
+f = 429 Hz
Answer: Oxygen
Explanation: Oxygen is the most common element in the human body. It makes up 65% of the body.
Answer:
Distance is directly proportional to the velocity
Explanation:
In 1929, Edwin Hubble's wrote an article that talked about relationship between the distance and recession speed/velocity of galaxies which led to what is known as the Hubble Law. This law states that galaxies are moving away from the earth at velocities proportional to their distances.
Thus is written as;
v = H_o•d
Where;
v is velocity
d is distance
H_o is Hubble's constant rate of cosmic expansion.
He came to this conclusion by generating a graph known as Hubble's classic graph which was a graph of observed velocity vs distance for nearby galaxies.
Static electricity travels to the door knob because of the friction caused by the feet on the carpet. the friction traveled through the person, to their hand, and to the door knob because it is the best conductor.
