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Inessa05 [86]
3 years ago
8

Which if the following doesn't cause an object to accelrate it's q 4

Physics
2 answers:
GarryVolchara [31]3 years ago
7 0

Change in direction, slowing down, and speeding up are all CHANGES of velocity, and THAT's called acceleration.

Constant velocity isn't a change of velocity, so it isn't called acceleration.

Slav-nsk [51]3 years ago
6 0

B. Constant velocity


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If the length and linear density are constant, the frequency is directly proportional to the square root of the tension.
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Signal words most often used in a chronological essay are
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<span>Chronological essays by the definition of a chronological meaning in order. There is an order in a specific writing. Like a history write up from a certain happening years ago.  It is different from procedural essays because these are essays who are giving instructions of certain set up to guide the person accordingly in doing something to make it more accurate. Like recipes, instructions in playing, etc. Example words that are used in chronological essays are first, second, third, fourth, fifth, next, after, then, lastly, finally, consequently, in addition, thus, therefore, however, etc.</span>
4 0
3 years ago
Read 2 more answers
A piece of aluminum has a volume of 1.50 10-3 m3. the coefficient of volume expansion for aluminum is β = 69 ✕ 10-6 (°c)-1. the
Alex17521 [72]

Answer:

W = 3.12 J

Explanation:

Given the volume is 1.50*10^-3  m^3 and the coefficient of volume for aluminum is β = 69*10^-6 (°C)^-1. The temperature rises from 22°C to 320°C. The difference in temperature is 320 - 22 = 298°C, so ΔT = 298°C. To reiterate our known values we have:

β = 69*10^-6 (°C)^-1       V = 1.50*10^-3  m^3       ΔT = 298°C

So we can plug into the thermal expansion equation to find ΔV which is how much the volume expanded (I'll use d instead of Δ because of format):

dV = \beta V_{0} dT\\dV = (69*10^{-6})( C)^{-1} * (1.50*10^{-3})m^{3} * (298)C\\dV = 3.0843*10^-5

So ΔV = 3.0843*10^-5 m^3

Now we have ΔV, next we have to solve for the work done by thermal expansion. The air pressure is 1.01 * 10^5 Pa

To get work, multiply the air pressure and the volume change.

W = P * dV = (1.01 * 10^5)Pa * (3.0843*10^{-5})m^3\\W = 3.115143J

W = 3.12 J

Hope this helps!

4 0
3 years ago
A ___________ is how strong the push or pull is
KatRina [158]
The answer is force
4 0
3 years ago
Question 2 (10 points)
kenny6666 [7]

The force required to slow the truck was -5020 N

Explanation:

First of all, we find the acceleration of the truck, which is given by

a=\frac{v-u}{t}

where

v is the final velocity

u is the initial velocity

t is the time

For the truck in this problem,

v = 11.5 m/s

u = 21.9 m/s

t = 2.88 s

So the acceleration is

a=\frac{11.5-21.9}{2.88}=-3.6 m/s^2

where the negative sign means that this is a deceleration.

Now we can find the force exerted on the truck, which is given by Newton's second law:

F=ma

where

m = 1390 kg is the mass of the truck

a=-3.6 m/s^2 is the acceleration

And substituting,

F=(1390)(-3.6)=-5004 N

So the closest answer among the option is -5020 N.

Learn more about acceleration and forces:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

8 0
2 years ago
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