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3 years ago

Which if the following doesn't cause an object to accelrate it's q 4

Physics

2 answers:

GarryVolchara [31]3 years ago

7 0

Change in direction, slowing down, and speeding up are all CHANGES of velocity, and THAT's called acceleration.

Constant velocity isn't a change of velocity, so it isn't called acceleration.

Slav-nsk [51]3 years ago

6 0

B. Constant velocity

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Answer:

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3 years ago

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Find the velocity. 10 points. Will give brainliest!

BARSIC [14]

Answer:

6.060606...

Explanation:

To figure out velocity, you divide the distance by the time it takes to travel that same distance, then you add your direction to it. So the distance would be 1000m and the time would be 2 minutes and 45 seconds and if you convert the minutes into fractions you would get 165 seconds than you would divide 1000m by 165 seconds and you would get 6.060606... seconds as her average velocity

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4 years ago

Identifying Applications of Electromagnetic Waves

Anuta_ua [19.1K]

Answer:

gamma ray-destruction of cancer cells

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3 years ago

A camera lens used for taking close-up photographs has a focal length of 22.0 mm. The farthest it can be placed from the film is

Arada [10]

Answer:

p = 6.64 cm

Explanation:

For this exercise we use the equation of the constructor

$\frac{1}{f} = \frac{1}{p} + \frac{1}{q}$

where f is the focal length, p and q are the distance to the object and the image, respectively

They tell us the focal length f = 2.2 cm and that the image as far as it can go is q = 3.29 cm, let's find the position of the object that creates this image

$\frac{1}{p} = \frac{1}{f} - \frac{1}{q}$

1 / p = 1 / 2.2 - 1/3.29

1 / p = 0.15059

p = 6.64 cm

therefore the farthest distance from the object is 6.64 c

3 0

3 years ago

Late one night on a highway, a car speeds by you and fadesinto the distance. Under these conditions the pupils of your eyes(aver

Andrews [41]

Answer:

10432.19076 m

Explanation:

$\lambda$ = Wavelength = 660 nm

d = Diameter of pupils = 6 mm

s = Distance between lights = 1.4 m

L = Distance from observer

From Rayleigh's criteria we have

$1.22\lambda=dsin\theta$

As $\theta$ is small $sin\theta=\dfrac{s}{L}$

So, the equation becomes

$1.22\lambda=d\dfrac{s}{L}\\\Rightarrow L=\dfrac{ds}{1.22\lambda}\\\Rightarrow L=\dfrac{6\times 10^{-3}\times 1.4}{1.22\times 660\times 10^{-9}}\\\Rightarrow L=10432.19076\ m$

The car is 10432.19076 m from me

6 0

4 years ago