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Verdich [7]
3 years ago
10

Work and power are different because

Physics
1 answer:
alina1380 [7]3 years ago
4 0

A) Work involves force and distance while power involves force and velocity

Hope this helps

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What is the colour of third band of a coded resistor having resistance equal equal to 2.3*10`2
Helen [10]

Color of third band of a coded resistor is Brown.

What is Resistance:

  • Resistance is a measure of the opposition to current flow in an electrical circuit.
  • Resistance is measured in ohms, omega (Ω)

The color code specify the resistance value, the tolerance, and sometimes the reliability or failure rate.

How to identify resistor's color codes:

  1. Look at the resistor so the group of 3 or 4 color bands are on the left side
  2. Read the color bands from left to right.
  3. Read the color on the last color band, which is farthest right.
  4. compare the colors to the resistance code table

Here,

the value of resistance is 2.3x10^2 Ω

R = 23x10^1 Ω

here power of 10 is 1

so, the color of third band of a color coded resistor will be related to number 1

Hence,

color of third band of a coded resistor is Brown.

Learn more about resistor's color codes here:

<u>brainly.com/question/24359143</u>

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#SPJ4

4 0
2 years ago
A circular area with a radius of 6.50 cm lies in the xy-plane. What is the magnitude of the magnetic flux through this circle du
White raven [17]

Answer:

a. \phi _B=3.0528\times10^-^3T\ m^2\\ \\b. \phi_B=1.83299\times10^-^3T\ m^2\\\\c.\phi_B=0

Explanation:

#Consider a circular area of radius R=2.98cm in the xy-plane at z=0. This means all the are vector points toward the +ve z-axis.

a. first, find the magnetic flux if the magnetic field has a magnitude of B=0.23T and points toward the +ve z-axis. The angle between the magnetic field and the area is \theta=0. Hence the magnetic flux:-

\phi _B=\int {\bar B} . d\bar A \\=\int BdAcos(\theta)=BAcos(0)=BA\\\\=\pi R^2B=\pi(6.50\times10^-^3m)^2(0.230T)\\=3.0528\times10^-^3 T\ m^2

Hence flux magnitude in +z direction is 3.0528\times10^-^3T \ m^2

b. We now find the magnetic flux when the field has a magnitude of <em>B=0.230T</em> and points at an angle of \theta=53.1\textdegree from the +z direction.

Magnetic flux is calculated as:

\phi _B=\int\bar B \bar dA\\=\int BdAcos (\theta)=BAcos(0)=BA\\=\pi R^2B=\pi(6.50\times 10^-^2m)^2(0.230T)\\=1.83299\times 10^-^3 T \ m^2

Hence the flux at an angle of 53.1\textdegree is 1.83299\times 10^-^3T \ m^2

c. We now need to find the magnetic flux if the field has a magnitue of B=0.230T and points in the direction of +y-direction. As with the previous parts, the magnetic flux will be calculated as:

\phi_B= \int\bar B \times d\bar A\\=\int BdAcos(\theta)\\=BAcos(90\textdegree)\\=0

Hence the magnetic flux in the +y-direction is zero.

3 0
3 years ago
I’ll give brainliest if it’s correct ;-;z
BlackZzzverrR [31]

Explanation:

what is the question? could you pls provide it

6 0
3 years ago
Riding a bicycle is this kind of long-term memory ______________
Schach [20]

answer

procedural memory ❤

8 0
3 years ago
HELP
liq [111]
It means that the soccer ball is a soccer ball bc it’s a soccer ball yk ?
7 0
3 years ago
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