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muminat
3 years ago
11

The directions are with the question. Please answer numbers 6 through 10, please.

Mathematics
1 answer:
prisoha [69]3 years ago
4 0

Answer:

6) 4 (tiny 5) in the upper corner

7) 9 (tiny 2) in the upper corner

8) 4 (tiny 2) in the upper corner

9) 3 (tiny4) in the upper corner

10) 5 (tiny 5) in the upper corner

Step-by-step explanation:

Once you get the hang of it, it's quite easy! Here are the steps for how I figured it out:

1) Figured out what number they are giving me. For the first one, I saw that they gave me the number 4. For the second one, they gave me the number 9 etc.

2) Next, I looked at each problem individually. For the first one, you know that they are giving you the number 4. You would then count the amount of numbers, in this case 4, that you see in the equation.

3) Now knowing the numbers of numbers in the equation, you'd write it in exponential notation. For the first one, they are giving you the number 4, however, they are giving it to you 5 times. Thus, by writing the number 5, smaller than the number 4, you are allowing you and your math teacher to know that you have to take the number 4 and multiply it by itself 5 times.

4) Try doing this for the others too. Trust me, once you get the hang of it, it's pretty simple. Hope this helped!

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A particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls invol
Phoenix [80]

Answer:

0.1091 or 10.91%

Step-by-step explanation:    

We have been given that a particular telephone number is used to receive both voice calls and fax messages. suppose that 20% of the incoming calls involve fax messages and consider a sample of 20 calls. We are asked to find the probability that exactly 6 of the calls involve a fax message.  

We will use Bernoulli's trials to solve our given problem.

P(X=x)=^nC_x\cdot P^x(1-P)^{n-x}

P(X=6)=^{20}C_6\cdot (0.20)^6(1-0.20)^{20-6}

P(X=6)=\frac{20!}{6!(20-6)!}\cdot (0.20)^6(0.80)^{14}

P(X=6)=\frac{20!}{6!(14)!}\cdot (0.000064)(0.04398046511104)

P(X=6)=38760\cdot (0.000064)(0.04398046511104)

P(X=6)=0.1090997009730

P(X=6)\approx 0.1091\\

Therefore, the probability that exactly 6 of the calls involve a fax message would be approximately 0.1091 or 10.91%.

4 0
3 years ago
Cory's average score after 8 tests is 91%. If he gets a 78% on his 9th test what will his new average be?
Luda [366]
You should be able to multiply 91 by 8 to get the sum of the first 8 tests, then add the score on the 9th test. Then to get the average of the sum of the 9 tests you need to divide it by 9.
((91*8)+78)/9=89.555555555555.... So, 90%
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3 years ago
Andre constructs the image of line n under a dilation centered at point O that is not on line n. Becca construct a different ima
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<em /><u><em /></u>I think that both lines will show only 1 line because 1 line will be on top of the other. I believe this because both lines are dilated with its center at point O which does not lie on line n. Whatever dilation Andre uses may also be the dilation used by Becca since their lines centered at point O. Both lines will have the same slope and share the same coordinates.
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I think the answer is 6 from the information you provided.
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Ira Lisetskai [31]
2x + 3x + 5x = 60
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6 0
3 years ago
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