It considered as Zero Gage pressure.
Answer:
T₂ = 2482.34 N
Explanation:
Equations of balance of forces
Look at the force diagram in the attached graph:
∑Fx=0
T₂cos α -T₁senα = 0 Equation (1)
∑Fy=0
T₁cos α +T₂sinα-W =0 Equation(2)
Data
m=539 kg
g= 9.8 m/s²
W= m*g= 539 kg* 9.8 m/s²= 5282.2 N
T₁ = 1.88T₂
Problem development
in the equation (1)
T₂cos α-(1.88T₂)senα = 0 We divided the equation by ( T₂cos α)
1 - (1.88)tanα = 0
tanα= 1/(1.88)
tanα= 0.5319

α = 28°
T₂=(1.88T₂)tanα
in the equation (2)
(1.88T₂)cos α+ T₂sinα - 5282.2 =0 We divided the equation by cos α
1.88T₂+ T₂tanα - 5282.2/cos α =0
1.88T₂+ T₂tan(28°) - 5282.2/(cos 28°) =0
1.88T₂+ (0.53)T₂- 5982.46 =0
(2.41)T₂ = 5982.46
T₂ = 5982.46/(2.41)
T₂ = 2482.34 N
To solve this problem it is necessary to apply the concepts related to Faraday's law and the induced emf.
By definition the induced electromotive force is defined as


Where,
Electric field
B = Magnetic Field
A = Area
At the theory the magnetic field is defined as,

Where,
N = Number of loops
I = current
Permeability constant
We know also that the cross sectional area, is the area from a circle, and the length is equal to the perimeter then
A = \pi r^2
l = 2\pi r
Replacing at the previous equation we have that

Where,
R = Radius of the solenoid
r = The distance from the axis
Re-arrange to find the current in function of time,

Replacing our values we have


The attractions between the particles in a liquid are strong enough to keep the particles close together. Without any significant attractions between particles in a gas, the particles are free to expand into any volume that is available