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natima [27]
3 years ago
12

Que es una ondaaaa?? no me deja escribiiiirrrrrr

Physics
1 answer:
UkoKoshka [18]3 years ago
7 0

Answer:

yo queiro escribir mi hermano

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How much energy (in joules) is released when 0.06 kilograms of mercury is condensed to a liquid at the same temperature?
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The answer is ....  C. 17,705.1 J
7 0
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A baseball is tossed straight up in the air. The table shows the height and velocity of the ball at different times as it moves
Akimi4 [234]

Answer: At that moment, all the baseball's kinetic energy has been converted to potential energy.

Explanation: I took the test

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2 years ago
A 2-kg ball is thrown at 3 m/s. What is the ball's momentum? *
crimeas [40]

Answer:

Given

mass (m) =2kg

velocity (v) =3m/s

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8 0
3 years ago
A) Charge q1 = +5.60 nC is on the x-axis at x = 0 and an unknown charge q2 is on the x-axis at x = -4.00 cm. The total electric
jeka94

Answer:

a) F₃₁ = 63.0 μN  

b) F₃₂ = - 14.0 μN

c) q₂ = - 5.0 nC

Explanation:

a)

  • Assuming that the three charges can be taken as point charges, the forces between them must obey Coulomb's Law, and can be found independent each other, applying the superposition principle.
  • So, we can find the force that q₁ exerts along the x-axis on q₃, as follows:

       F_{31} =\frac{k*q_{1}*q_{3} }{r_{13}^{2}} = \frac{9e9Nm2/C2*5.6e-9C*2.0e-9C}{(0.04m)^{2}}  = 63.0 \mu N   (1)

b)

  • Since total force exerted by q₁ and q₂ on q₃ is 49.0 μN, we can find the force exerted only by q₂ (which is along the x-axis only too) just by difference, as follows:

      F_{32} = F_{3} - F_{31}  = 49.0\mu N  - 63.0\mu N = -14.0 \mu N  (2)

c)

  • Finally, in order to find the value of q₂, as we know the value and sign of F₃₂, we can apply again the Coulomb's Law, solving for q₂, as follows:

      q_{2}  = \frac{F_{32} * r_{23}^{2} }{k*q_{3}} = \frac{(-14\mu N)*(0.08m)^{2}}{9e9Nm2/C2* 2 nC} = - 5 nC  (3)

6 0
3 years ago
How high was a brick dropped from if if falls in 2.5 seconds?
jenyasd209 [6]
Using the kinematic equation d =  V_0 * t  + 1/2 * a * t^2, where d is height you can rewrite this to be d = 1/2*g*t^2 or 4.9t^2
g = a because this is a free fall 
d = 1/2 * 9.81m/s^2 * 2.5^2
d = 30.65625m
d = 30.7m
7 0
3 years ago
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