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serg [7]
3 years ago
7

When you lift a box off the ground gravity opposes your lifting force.

Physics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

TRUE?

Explanation:

Im not really sure what your question is.

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Describe the difference between the currents that exist in the wires leading to a capacitor when these wires are connected to (a
krek1111 [17]

Answer:

Explanation: In DC circuit, the current will flow for a short time, which is required to charge the capacitor. Once you switch it on, it spikes and the gradually decreases to almost zero (0) as the capacitor becomes fully charged.

In an AC circuit, the circuit acts as if the current is flowing throw the plates whereas is not actually flowing. The circuit acts like the AC is flowing through the capacitor.

8 0
3 years ago
A student performs Young’s double-slit experiment with slits that are separated by 0.160 mm. She observes the interference patte
Bogdan [553]

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Wavelenght is 4.53x10^-7m

Explanation:

Detailed explanation and calculation is shown in the image below

5 0
2 years ago
When waves interfere together and result in a quieter sound is called
Alexus [3.1K]
That is called fully constructive interference.
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3 years ago
Consider the reaction, X + 2Y → XY2 If X and Y are completely consumed in the reaction and we start with 10.0 mol of Y, then how
Harrizon [31]

Answer:

In the reaction you would have 15.0 mols of Y and X.

Explanation:

The stoichiometric coefficents for X and Y are 1 and 2 respectively, if you start the reaction with 10.0 moles of Y you would need 5.0 moles of X in order to achieve a complete reaction so you will have 15.0 total moles in the reaction, assuming no mass loss and no nuclear reactions.

3 0
3 years ago
Please help ASAP. A car engine with a mass of 1750 kg can exert 215 000 W. a) How long will it take the car to reach 95.0 km/h i
tensa zangetsu [6.8K]
<h2>Answer:</h2><h3><u>QUESTION①)</u></h3>

<em>✔ First step : calculate the kinetic energy that this car requires to reach 95 km/h</em>

95/ 3,6 ≈ 26,4 m/s  

<em>Ec = ½ m x V²  </em>

With Ec in J; m in kg; and V in m/s  

  • Ec = ½ 1750 x 26,4²  
  • Ec ≈ 610 000 J

<em>✔ Knowing that the car has a p power of 215,000 W, so : </em>

T = E/P  

  • T = 610 000/215 000  
  • T ≈ 2.8 s
<h3>The car takes 2.8 s to reach 95 km/h </h3>

<h3><u>QUESTION②)</u></h3>

N = 2,8/6,5 x 100 = 43.07

<h3>The car efficiency is 43 % </h3>
5 0
3 years ago
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