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3 years ago

While skiing in Jackson, Wyoming, your

1 answer:

8 0

Hello!

Work is equal to negative change in PE and PE=mgh and Power is change in work/change in time

So we have

56.1kg * 9.80m/s^2 * 16m = 8796.5 J of PE at top of run and -8796.5J of work done also

if it takes him 12s then we need to find the time gravity alone would bring him to the bottom. we get

16m=1/2at^2 and solving for t we get
t=sqrt(32/9.80m/s^2)=1.81s

so the difference in time is 12-1.8=11.2s

now we can find avg power=work/time = 8796.5J/11.2s = 785W or 785J/s

Hope this helps! Any questions please ask! Thank you!

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Dima020 [189]

Answer:

False

Explanation:

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3 years ago

Read 2 more answers

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castortr0y [4]

The first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Given data:

The value of the first distance is, d1 = 0.25 m.

The value of the second distance is, d2 = 0.50 m.

The ratio of distance covered by an object in a specific direction and the time taken to cover the distance is known as the velocity of the object. Mathematically, the expression for the velocity is,

v = d/t

Here,

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t is the average time taken to cover the distance.

Then the first velocity of the car at 0.25 m is,

v1 = d1/t1

v1 = 0.25 / t1

here, t1 is the average time for first distance.

And the second velocity of the car with four washers at the 0. 50 m mark is,

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here, t2 is the average time for the second distance.

Thus, we can conclude that the first and second velocities of the car are 0.25/t1 and 0.50/t2 respectively.

Learn more about the velocity here:

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2 years ago

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Therefore the molecules of water moved slower and stated moving in place (i.e vibrating at a point). The water turns to an ice.

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3 years ago

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JulsSmile [24]

Choice - B is the correct one.

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