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jeka57 [31]
4 years ago
12

Which planet is to humankind?

Physics
1 answer:
Maslowich4 years ago
3 0
Earth. Only. Any other known planets are inapplicable.
You might be interested in
A long solenoid with 8.22 turns/cm and a radius of 7.00 cm carries a current of 19.4 mA. A current of 3.59 A exists in a straigh
daser333 [38]

Answer:

a. 3.039cm

b.magnetic field is B=2.958\times10^{-5}T

Explanation:

Direction of the solenoid magnetic field is along the axis of the solenoid. and magnetic field due to the wire perpendicular to that due to the solenoid.. Magnetic field at r is given by:

\overrightarrow B = \overrightarrow B_s+ \overrightarrow B_w,\ \ \ \ \  \overrightarrow B_s\perp \overrightarrow B_w

Angle of net magnetic field from axial direction is given by:

tan\  \theta=\frac{B_w}{B_s},

Field due to solenoid:

B_s=\mu_onI_s,  \ \ \ \ n=(8.22 t/cm)(100cm/m)=822turn/m

Field due to wire:

B_w=\frac{\mu_oI_w}{2\pi r}

Therefore, r:

tan\  \theta=\frac{B_w}{B_s}\\\\=\frac{\mu_oI_w}{2\pi r(\mu_o nI_s)}\\\\r=\frac{I_w}{2\pi  nI_stan \ \theta}\\\\r=\frac{3.59A}{2\pi\times822\times19.4\times10^{-3}A \ tan 49.7\textdegree}\\\\r=3.039cm

Hence, the radial distance is 3.039cm

b.The magnetic field strength is given by:

B=\sqrt{B_w^2+B_s^2}\\\\tan 49.7\textdegree=\frac{B_w}{B_s}\\\\1.179=\frac{B_w}{B_s}\\\\B_w=1.179B_s\\\\B=\sqrt{(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{3}A)+1.179(4\pi\times10^{-7}T.m/A\times 822\times19.4\times10^{-3}A)}\\\\B=2.958\times10^{-5}T

Hence, the magnetic field is B=2.958\times10^{-5}T

7 0
4 years ago
I need help with number 23!! Please
Juliette [100K]
Ah hah !  There's an easy way and a hard way to do this one.
If it's OK with you, I'm gonna do it the easy way, and not even
talk about the hard way !

First, let's look at a few things in this question.

-- "gravitational force between a planet and a mass"
    This is just a complicated way to say "How much does the mass weigh ?"
    That's what we have to find.

-- If we know the mass, how do we find the weight ?
   Multiply the mass by the acceleration of gravity there.
   Weight = (mass) x (gravity) .

-- Do we know the acceleration of gravity on this dark mysterious planet ?
    We do if we read the second line of the question !  
    It's right there ... 8.8 m/s² .

-- We know the mass.  We know gravity.  And we know that
    if you multiply them, you get the weight (forced of gravity).

I'm pretty sure that you can do the rest of the solution now.

weight = (mass) x (gravity)

Weight = (17 kg) x (8.8 m/s²)

Multiply them:

Weight = 149.6  kg-m/s²

That complicated-looking unit is the definition of a Newton !

So the weight is  149.6 Newtons.  That's the answer.  It's choice-A.
It's about 33.6 pounds.

When this mass is on the Earth, it weighs about 37.5 pounds.
But when it's on this planet, it only weighs about 33.6 pounds.
That's because gravity is less on this planet. (8.8 there, 9.8 on Earth)
3 0
3 years ago
Compute the longitudinal strength of an aligned carbon fiber-epoxy matrix composite having a 0.25 volume fraction of fibers, ass
zmey [24]

Answer:

632.5 MPa

Explanation:

\sigma_{m} = Matrix stress at fiber failure = 10 MPa

V_f = Volume fraction of fiber = 0.25

\sigma_f = Fiber fracture strength = 2.5 GPa

The longitudinal strength of a composite is given by

\sigma_{cl}=\sigma_{m}(1-V_f)+\sigma_fV_f\\\Rightarrow \sigma_{cl}=10(1-0.25)+(2.5\times 10^3)\times 0.25\\\Rightarrow \sigma_{cl}=632.5\ MPa

The longitudinal strength of the aligned carbon fiber-epoxy matrix composite is 632.5 MPa

8 0
3 years ago
A dog sees a flowerpot sail up and then back past a window 5.0 ft high. If the total time the pot is in sight is 1.0 seconds, fi
Kisachek [45]

To solve this problem we will use the linear motion kinematic equations for which acceleration (in this case gravity) is described as the change in velocity in an instant of time. Subsequently through the energy conservation equations we will find the net height.

Let's start considering that the time is 1 second, therefore,

t = 1s

Now the acceleration would be given as

g = \frac{\Delta v}{t}

g = \frac{v_f-v_i}{t}

v_f-v_i = gt

Since the final speed is zero, and the time elapsed to reach the height is 0.5 seconds (half of the entire route) we will have that the initial speed can be expressed in terms of gravity as

0-v_i = g(\frac{1}{2})

v_i = \frac{1}{2} g

Now for energy conservation, the potential energy must be equal to the kinetic energy, therefore,

PE = KE

mgh = \frac{1}{2} mv_i^2

h = \frac{v_i^2}{2g}

Replacing the previous value found,

h = \frac{1}{4} \frac{g^2}{2g}

h = \frac{1}{4} \frac{9.8^2}{2(9.8)}

h = 1.225m

Therefore the hegiht above the windows that the pot rises is 1.225m

4 0
3 years ago
Consider the following forces. (1) frictional (2) gravitational (3) tension (4) strong nuclear (5) normal (6) electroweak which
Scorpion4ik [409]

The forces listed are considered fundamental forces (2) gravitational (4) strong nuclear (6) electroweak.

Fundamental force, also called fundamental interaction, in physics, is any of the four primary forces—gravitational, electromagnetic, sturdy, and weak—that govern how gadgets or particles interact and how certain particles decay. All of the regarded forces of nature may be traced to those essential forces.

Now, physicists say they have discovered viable symptoms of a fifth essential force of nature. The findings come from studies performed at a laboratory near Chicago. The four fundamental forces govern how all of the objects and particles inside the Universe engage with each other.

The strong nuclear pressure pulled definitely and negatively charged quarks collectively to form undoubtedly charged protons and neutrally charged neutrons. The strong nuclear force also binds protons and neutrons within the nucleus of atoms. The weak nuclear force enabled complicated atoms to form through nuclear fusion.

Learn more about the fundamental forces here brainly.com/question/910002

#SPJ4

4 0
2 years ago
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