Part of the scientific process involves sharing your results with other scientists. To do this, we all need to use the same measurement system, which you'll learn about in this lesson.
Imagine you're trying to find out how much an elephant weighs. You're pretty sure it weighs a lot, but you don't know the exact number. So you ask your teacher, and she tells you an elephant weighs the same as three hippos.
Well that's nice to know, but how much does a hippopotamus weigh? Again, you ask your teacher, and she tells you a hippopotamus weighs the same as five alligators. That's a cool fact to know, but you still don't understand how much an elephant weighs because comparing elephants to alligators can be confusing.
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I will answer both versions assuming what you want to know is the distance it travels up from and over the ground. and how long until it reaches space. 540 meters per second up and over. to reach space which is 100km above sea level, it would take about 5400 minutes
Answer:
1.7 L
Explanation:
PV = nRT
If P, n, and R are constant:
V₁ / T₁ = V₂ / T₂
(2.0 L) / (293.15 K) = V / (255.15 K)
V = 1.7 L
OF2 -
<span>O has 6 electrons in outer shell and F has 7 in its outer shell </span>
<span>Therefore, you have to account for 20 electrons total in the </span>
<span>structure (7+7+6 = 20) </span>
<span>therefore draw it linear first. F ---- O-----F </span>
<span>The two bonds take care of 4 electrons now you have to add another 16. </span>
<span>Therefore 3 lone pairs on each F and 2 lone pair on O. </span>
<span>If you check for formal charges, all the atoms are neutral </span>
<span>F will have 3 lone pairs + 1 bond = 7 electrons (bond = 1/2 electron for formal charge distribution) therefore both the F's are neutral </span>
<span>Now look at the O: it should have 6.. it has two lone pair and 2 bonds = 4 electrons and 2 bonds = 1 electron each = 2 electrons from bonds = 6 total electrons for formal charge which is exactly the # it should have. There is no need for any double bond in this as there are no charges to be separated. </span>
<span>Now if u look at the # of domains around O you will see if you include the lone pairs it has a sp3 hybridization (4 domains) therefore a tetrahedron which has 2 lone pairs and 2 bonds.. since there are two lone pairs, the lone pair/bond pair repulsion is so high it is going to repel the two Fluorines and form a bent structure, looks a lot like H2O. </span>
The answer to this is there maturity.
