Answer:

Step-by-step explanation:

<h3>Can I have the brainliest please?</h3>
Part 1:
180 = 5p+98 + 9p-2
180 = 14p + 96
84 = 14p
6 = p
part 2:
angle S will be the same as angle Q, so:
9p-2
9(6)-2
54-2
M
It is the third equation: −512⋅(65⋅13)⋅92=(−512⋅65)⋅(13⋅92)
Associative property means one can group the individual operations arbitrarily without changing the result.
The volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
<h3>What is the volume of right square pyramid?</h3>
The volume of a square pyramid is expressed as;
V = (1/3)a²h
Where a is the base length and h is the height of the pyramid
Given that;
- Base edges of the square base a = 64cm
- Slant height s = 40cm
- Height of the pyramid h = ?
- Volume = ?
First, we determine the height of the pyramid using Pythagorean theorem.
c² = a² + b²
- c = s = 40cm
- a = half of the base length = a/2 = 64cm/2 = 32cm
- b = h
(40cm) = (32cm)² + h²
1600cm² = 1024cm² + h²
h² = 1600cm² - 1024cm²
h² = 576cm²
h = √576cm²
h = 24cm
Now, we calculate the volume of the right square pyramid;
V = (1/3)a²h
V = (1/3) × (64cm)² × 24cm
V = (1/3) × 409664cm² × 24cm
V = 32768cm³
Therefore, the volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.
Learn more about volume of pyramids here: brainly.com/question/27666514
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