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pshichka [43]
3 years ago
14

What is the sum of the polynomials?

Mathematics
2 answers:
Inessa [10]3 years ago
7 0
-4x^2  - 11x + 13. :)
Nadya [2.5K]3 years ago
6 0

For this case we have the following polynomials:

-x ^ 2 + 9\\-3x ^ 2 - 11x + 4

Adding the polynomials we have:

(-x ^ 2 + 9) + (-3x ^ 2 - 11x + 4)

Rewriting we have:

x ^ 2 (-1-3) - 11x + (9 + 4)

Therefore, the result of the sum is:

-4x ^ 2 - 11x + 13

Answer:

the sum of the polynomials is:

-4x ^ 2 - 11x + 13

option 2

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Which equation applies the associative property of multiplication? ​(−14−53)−35=−14−(53−35)​ ​ (−78⋅25)+(−78⋅35)=−78⋅(25+35) ​ ​
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It is the third equation: −512⋅(65⋅13)⋅92=(−512⋅65)⋅(13⋅92)

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What is the volume, in cubic centimeters, of a right square pyramid
HACTEHA [7]

The volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.

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The volume of a square pyramid is expressed as;

V = (1/3)a²h

Where a is the base length and h is the height of the pyramid

Given that;

  • Base edges of the square base a = 64cm
  • Slant height s = 40cm
  • Height of the pyramid h = ?
  • Volume = ?

First, we determine the height of the pyramid using Pythagorean theorem.

c² = a² + b²

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(40cm) = (32cm)² + h²

1600cm² = 1024cm² + h²

h² = 1600cm² - 1024cm²

h² = 576cm²

h = √576cm²

h = 24cm

Now, we calculate the volume of the right square pyramid;

V = (1/3)a²h

V = (1/3) × (64cm)² × 24cm

V = (1/3) × 409664cm² × 24cm

V = 32768cm³

Therefore, the volume of the right squared pyramid with the given base edges and slant height is 32768 cubic centimeters.

Learn more about volume of pyramids here: brainly.com/question/27666514

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