$1.65 THAT IS CLEARLY THE ANSWER BEACEUSE EACH CAN IS 33 CENTS SO 5 CANS IS 33 * 5= 1.65
Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet
Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat
By Pythagoras theorem
AC^2 = AB^2 + BC^2
(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)
AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)
Therefore they have cover a distance of 25 * (under root 11)
The problem is asking us to isolate B. The given equation is solved for P, and we need to rearrange it for B.
First we need to square both sides. This will cancel out the square root on the right side.
P^2 = E + A^2/B^2
Next, subtract E from both sides.
P^2 - E = A^2/B^2
Next we need to get the B^2 out of the denominator. Multiply both sides by B^2.
B^2(P^2 - E) = A^2
Next divide both sides by (P^2 - E).
B^2 = A^2/(P^2 - E)
Lastly, take the square root of both sides.
B = sqrt(A^2/(P^2 - E))
Answer:
256
Step-by-step explanation:
and if u need in simpliest form just ask me
Answer:
x= -1.24, 3.24
Step-by-step explanation:
x² – 2x=4
Bring 4 over
x² – 2x - 4=0
Quadratic formula:
if ax²+bx+c=0
the (+-) = ±
= 3.24
= -1.24
