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3 years ago

The value of x is and the value of y is

Mathematics

2 answers:

Fittoniya [83]3 years ago

7 0

Answer:

Step-by-step explanation:

Angles in a triangle add up to 180 degrees.

x + 70 + 50 = 180

x + 120 = 180

x = 60

The other triangle's missing angle:

180 - 60 - 50 = 70

Angles on a straight line add up to 180 degrees.

70 + x + y = 180

We know the value of x.

70 + 60 + y = 180

Solve for y.

130 + y = 180

y = 180 - 130

y = 50

TEA [102]3 years ago

6 0

Answer:

x = 60, y = 50

Step-by-step explanation:

60 + 50 = 110 + 70 = 180.

50 + 70 = 120 + 6 = 180.

Therefore 50 + 70 + x = 60

Therefore 70 + 60 + y = 50

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Answer:

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3 years ago

Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form

Anestetic [448]

Answer:

Final answer is $x-6y=23$

Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

So first we need to find the slope of given line.

rewirite x=6y-5 in y=mx+b form

x+5=6y

$\frac{1}{6}x+\frac{5}{6}=y$

Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

$y-y_1=m\left(x-x_1\right)$

$y-(-3)=\frac{1}{6}\left(x-5\right)$

$y+3=\frac{1}{6}x-\frac{5}{6}$

$y=\frac{1}{6}x-\frac{5}{6}-3$

$y=\frac{1}{6}x-\frac{23}{6}$

Now we need to rewrite that equation in standard form. Ax+By=C.

6y=x-23

x-23=6y

x-6y=23

Hence final answer is $x-6y=23$

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3 years ago

Kristen worked 39 hours in 6 days

Fittoniya [83]

<h2>39/6 = 6.5</h2><h2 /><h2>6 hours 30 minutes</h2>

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3 years ago

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Is t-8=3t+1 a solution , no solution or a infinite solution

olasank [31]

T = -4.5

Answer is One solution.

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3 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

EleoNora [17]

Check the picture below.

so... you can pretty much see how long RS and QT are, you can just count the units off the grid.

now, let's find QR's length

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&Q&(~ 8 &,& 8~) 
% (c,d)
&R&(~ 14 &,& 16~)
\end{array}~~ 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
QR=\sqrt{(14-8)^2+(16-8)^2}\implies QR=\sqrt{6^2+8^2}
\\\\\\
QR=\sqrt{36+64}\implies QR=\sqrt{100}\implies QR=10$

and let's also find the length for ST

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&S&(~ 20 &,& 16~) 
% (c,d)
&T&(~ 22 &,& 8~)
\end{array}~ 
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
ST=\sqrt{(22-20)^2+(8-16)^2}\implies ST=\sqrt{2^2+(-8)^2}
\\\\\\
ST=\sqrt{4+64}\implies ST=\sqrt{68}\implies ST=\sqrt{4\cdot 17}
\\\\\\
ST=\sqrt{2^2\cdot 17}\implies ST=2\sqrt{17}$

so, add the lengths of all sides, and that's the perimeter of the trapezoid.

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3 years ago

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