There is no illustration of the problem provided but I'll attempt to provide an answer.
The relationship between the electric potential difference between two points and the average strength of the electric field between those two points is given by:
║E║ = ΔV/d
║E║ is the magnitude of the average electric field, ΔV is the potential difference between A and B, and d is the distance between A and B.
We are given the following values:
║E║= 10N/C
d = 3m
Plug these values in and solve for ΔV
10 = ΔV/3
ΔV = 30V
Answer:
3.675 m
Explanation:

X-direction | Y-direction
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Hope it helps
Answer: Nuclear energy is released from an atom through one of two processes: nuclear fusion or nuclear fission. In nuclear fusion, energy is released when the nuclei of atoms are combined or fused together. This is how the sun produces energy. In nuclear fission, energy is released when the nuclei of atoms are split apart.
Let me know if it helps!

Let's start by finding the time it takes for the dog to reach a velocity of
m/s.
We can use the following equation, where
is initial velocity,
is final velocity,
is time, and
is acceleration.

We're trying to solve for
first, so divide both sides by
.

Substitute in the known values.



Now, we can use the following formula to find the distance.

Substitute in the known values.

Anything multiplied by
is

Just simplify from there.




Answer:
Frictional force will be equal to 126.04 N
Explanation:
We have given mass of the bullet m = 28 gram = 0.028 kg
Initial velocity u = 55 m /sec
Width of sand = 30 cm = 0.3 m
So initial kinetic energy 
Final velocity of the bullet v = 18 m /sec
So final kinetic energy 
So change in kinetic energy = 42.35 - 4.536 = 37.814 j
From work energy theorem this change in kinetic energy will be equal to work one by frictional force
So 
