The energy in the system is given by the law of conservation of energy.
The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h.
Reason:
The given parameters are;
Surface of the inclined plane = Frictionless
Potential energy at the horizontal line = Zero of gravitational potential
By the law of Conservation of Energy, we have;
The spring will be compressed by a distance, <em>x</em>
The energy stored in the compressed spring, K.E. = (1/2)·k·x²
Energy in the block when the block comes to rest at a height, h₁, will be, P.E. = m·g·h₁
Therefore, by conservation of energy, we have;
The initial potential of the block = The stored energy in the compressed string + The gravitational potential energy of the block when it has compressed.
Therefore, the correct option is; <u>The energy stored in the spring plus the gravitational potential energy of the block when it has fully compressed the spring will be equal to m·g·h</u>
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