The quotient of 12 and the product of 5 and t is:
![\frac{12}{5t}](https://tex.z-dn.net/?f=%20%5Cfrac%7B12%7D%7B5t%7D%20%20)
Answer:
x is greater than 0
Step-by-step explanation:
solving the inequality gives x value of greater than 0.
so on the number line from 0 to infinity
Answer:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29)
And for this case we can use the cumulative distribution function given by:
![P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b](https://tex.z-dn.net/?f=%20P%28X%5Cleq%20x%29%20%3D%5Cfrac%7Bx-a%7D%7Bb-a%7D%2C%20a%20%5Cleq%20x%20%5Cleq%20b)
And using this formula we have this:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29%3D%20%5Cfrac%7B12000-10100%7D%7B14700-10100%7D%3D%200.41)
Then we can conclude that the probability that your bid will be accepted would be 0.41
Step-by-step explanation:
Let X the random variable of interest "the bid offered" and we know that the distribution for this random variable is given by:
![X \sim Unif( a= 10100, b =14700)](https://tex.z-dn.net/?f=%20X%20%5Csim%20Unif%28%20a%3D%2010100%2C%20b%20%3D14700%29)
If your offer is accepted is because your bid is higher than the others. And we want to find the following probability:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29)
And for this case we can use the cumulative distribution function given by:
![P(X\leq x) =\frac{x-a}{b-a}, a \leq x \leq b](https://tex.z-dn.net/?f=%20P%28X%5Cleq%20x%29%20%3D%5Cfrac%7Bx-a%7D%7Bb-a%7D%2C%20a%20%5Cleq%20x%20%5Cleq%20b)
And using this formula we have this:
![P(X](https://tex.z-dn.net/?f=%20P%28X%3C12000%29%3D%20%5Cfrac%7B12000-10100%7D%7B14700-10100%7D%3D%200.41)
Then we can conclude that the probability that your bid will be accepted would be 0.41