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Margarita [4]
3 years ago
12

Help me please I really need help

Mathematics
1 answer:
Troyanec [42]3 years ago
5 0

Answer: Find the area of all figures and then add it together

Step-by-step explanation:

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Which shows two expressions that are equivalent to (Negative 7) (Negative 15) (Negative 5)? (Negative 7) (Negative 75) and (Nega
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1 3 and 4

Step-by-step explanation:

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Select the correct answer.
kobusy [5.1K]

9514 1404 393

Answer:

  A.  f^-1(x) = x³ -12

Step-by-step explanation:

The inverse function can be found by solving ...

  x = f(y)

  x = ∛(y +12) . . . . . use the definition of f(x)

  x³ = y +12 . . . . . . . cube both sides to eliminate the radical

  x³ -12 = y . . . . . . . add -12 to isolate the y-variable

  f^-1(x) = x³ -12 . . . matches choice A

7 0
3 years ago
Line segmentAB has vertices A(−3, 4) and B(1, −2) . A dilation, centered at the origin, is applied to AB⎯⎯⎯⎯⎯ . The image has ve
zysi [14]

Answer:

The scale factor is

\frac{1}{3}

Step-by-step explanation:

Line segmentAB has vertices A(−3, 4) and B(1, −2) .

A dilation, centered at the origin, is applied to AB. The image has vertices

A'(-1,4/3) and B′(1/3, −2/3) .

We know the rule for dilation by scale factor of k, is

(x,y)\to(kx,ky)

This means that;

A(-3,4)\to A'(-3k,4k)

But we know, A' has coordinates (-1,4/3)

This means that

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k =  \frac{1}{3}

We could also compare:

4k=4/3

Which gives

k=⅓

5 0
3 years ago
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24% of U.S. adults say they are more likely to make purchases during a sales tax holiday. you randomly select 10 adults. find th
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Answer:

a) p(X= 2) = 0.261

b) P(x>2) = 0.566

c) P(2<x<5)  = 0.334

Step-by-step explanation:

Given 24% of U.S. adults say they are more likely to make purchases during a sales tax holiday

Probability 0f U.S. adults say they are more likely to make purchases during a sales tax holiday (p) = 0.24

                            n = 10

By using Poisson distribution

mean number of make purchases during a sales tax holiday

λ = np = 10 X 0.24 = 2.4

a)

The probability of getting exactly '2'

The probability p(X= 2) = e^{-\alpha } \frac{\alpha^r }{r! }

p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }

p(X= 2) = e^{2.4 } \frac{\(2.4)^2 }{2! }= 0.261

b) The probability of getting more than '2'

P(X>2) = 1- {p(x=0)+p(x=1)+p(x=2)}

                = e^{-2.4 } \frac{(2.4)\^0 }{0! }+ e^{-2.4 } \frac{(2.4)\^1 }{1!}+e^{-2.4 } \frac{(2.4)\^2 }{2!}

              = 0.090 + 0.2177+0.261 = 0.566

P(x>2) = 0.566

c) The probability of getting between  two and five

P( 2<x<5) = P(x=3)+p(x=4) == e^{-2.4 } \frac{(2.4)\^3 }{3! }+ e^{-2.4 } \frac{(2.4)\^4 }{4!}+

P(2<x<5) = 0.2090 + 0.125 = 0.334

4 0
3 years ago
What is the name of this figure:
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Answer:

tringular prism

Step-by-step explanation:

there u go

4 0
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