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Hoochie [10]
3 years ago
9

Yesterday, Linda had 71 baseball cards. Today, she gave d away. Using d, write an expression for the number of cards Linda has l

eft.
Mathematics
2 answers:
zvonat [6]3 years ago
8 0
71-d


EXPLAINING:
So you start with 71. And you know she gave some away therefore you subtract. It gives you a variable to use as well.

dezoksy [38]3 years ago
3 0

Answer:

71-d

Step-by-step explanation:

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HELPPPP 100 points if you help!!!!
nignag [31]

Answer:

Part A)

Chorus:

c(t)=15(1.12)^t

Band:

b(t)=2t+30

Part B)

After 9 years:

The chorus will have about 41 people.

And the band will have 48 people.

Part C)

About approximately 11 years.

Step-by-step explanation:

We are given that there are 15 people in the chorus. Each year, number of people in the chorus increases by 12%. So, the chorus increases exponentially.

There are 30 people in the band. Each year, 2 new people join the band. So, the band increases linearly.

Part A)

Since after each year, the number of people in the chorus increases by 12%, the new population will be 112% or 1.12 of the previous population.

So, using the standard form for exponential growth:

c(t)=a(r)^t

Where <em>a</em> is the initial population and <em>r</em> is the rate of change.

We will substitute 15 for <em>a </em>and 1.12 for <em>r</em>. Hence:

c(t)=15(1.12)^t

This represents the number of people in the chorus after <em>t</em> years.

We are given that 2 new people join the band each year. So, it increases linearly.

Since there are already 30 people in the band, our initial point or y-intercept is 30.

And since 2 new people join every year, our slope is 2. Then by the slope-intercept form:

b(t)=mt+b

And by substitution:

b(t)=2t+30

This represents the number of people in the band after <em>t</em> years.

Part B)

We want to find the number of people in the chorus and the band after 9 years.

Using the chorus function, we see that:

c(9)=15(1.12)^9\approx41.59\approx41

There will be approximately 41 people in the chorus after 9 years.

And using the band function, we see that:

b(9)=2(9)+30=48

There will be 48 people in the band after 9 years.

Part C)

We want to determine after approximately how many years will the number of people in the chorus and band be equivalent. Hence, we will set the two functions equal to each other and solve for <em>t</em>. So:

15(1.12)^t=2t+30

Unfortunately, it is impossible to solve for <em>t</em> using normal analytic methods. Hence, we can graph them. Recall that graphically, our equation is the same as saying at what point will our two functions intersect.

Referring to the graph below, we can see that the point of intersection is at approximately (10.95, 51.91).

Hence, after approximately 11 years, both the chorus and the band will have approximately 52 people.

5 0
3 years ago
What is 5/7 in the simplest form
Alexeev081 [22]
Exact form: 
5/7

Decimal form:
0.71428571... 


3 0
3 years ago
45 times gives me a 100
GaryK [48]

Answer: what’s your question?

Step-by-step explanation:

7 0
2 years ago
Six cakes cost $2.40 so how much do 10 cakes cost?
Gemiola [76]
6c...........2.40\$ \\ 10c...........x \\\\ x=\frac{2.40*10}{6}= \frac{24.0}{6} \\\\ \boxed{x=4\$}
5 0
3 years ago
Read 2 more answers
An equation parallel and perpendicular to 4x+5y=19
UNO [17]

Answer:

Parallel line:

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

y=\frac{5}{4}x-\frac{1}{2}

Step-by-step explanation:

we are given equation 4x+5y=19

Firstly, we will solve for y

4x+5y=19

we can change it into y=mx+b form

5y=-4x+19

y=-\frac{4}{5}x+\frac{19}{5}

so,

m=-\frac{4}{5}

Parallel line:

we know that slope of two parallel lines are always same

so,

m'=-\frac{4}{5}

Let's assume parallel line passes through (1,1)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-1=-\frac{4}{5}(x-1)

now, we can solve for y

y=-\frac{4}{5}x+\frac{9}{5}

Perpendicular line:

we know that slope of perpendicular line is -1/m

so, we get slope as

m'=\frac{5}{4}

Let's assume perpendicular line passes through (2,2)

now, we can find equation of line

y-y_1=m'(x-x_1)

we can plug values

y-2=\frac{5}{4}(x-2)

now, we can solve for y

y=\frac{5}{4}x-\frac{1}{2}


4 0
3 years ago
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