The answer is c hope it’s right
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
Answer:
The other factor is 
Step-by-step explanation:
we know that


In this problem we have

and
-----> because is a factor
substitute and solve for b

so

Verify in the second equation
----->
----->
--> is ok
The other factor is 
Answer:
B
Step-by-step explanation:
To go from 6 to 9 you'd first have to divide 6 by 2 and the multiply by 3,
so
x 3 = 
Answer:
35+15s+15s-25t-20t
and 35+20s+10s-15t-30t
Step-by-step explanation:
i tried