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3 years ago

HELP!

Mathematics

2 answers:

Akimi4 [234]3 years ago

4 0

Answer:

Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

There will be 8 triangles made.

The center angle will be = $\frac{360}{8}=45$

The triangle will be formed an isosceles triangle, so remaining angle will be :

$\frac{180-45}{2}=67.5$

$sin 67.5=\frac{opposite}{5}$

opposite= CD = $5sin67.5=4.6194$

Similarly,

adjacent = BD = $5cos67.5=1.9134$

The complete AB will be = $2*1.9134=3.8268$

Area of triangle ABC will be = $\frac{1}{2}*base*height = \frac{1}{2}*3.8268*4.6194=8.838$

So, the area of octagon will be 8 times area of this triangle.

Area of octagon will be = $8*8.838=70.70$

Hence are the area of octagon is 70.70 : Option D : Answer

Hope it will help :)

Nuetrik [128]3 years ago

3 0

the answer is d I know this one

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Is 4/10 bigger than 4/100

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Answer:

Yes

Step-by-step explanation:

4/10 = 0.4

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Therefore the answer is yes

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3 years ago

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)

Lemur [1.5K]

Answer:

Cardiac output: $F=0.055 L\s$

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output: $F=\frac{A}{\int\limits^T_0 {c(t)} \, dt}$ ---1

A = 3 mg

$\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt$

Do, integration by parts

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}$

$[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}$

Substitute the value in 1

Cardiac output: $F=\frac{3}{54.49}$

Cardiac output: $F=0.055 L\s$

Hence Cardiac output: $F=0.055 L\s$

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3 years ago

Please help, am i right

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Answer: yea you are

Step-by-step explanation:

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4 years ago

Find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3). express answer in standard form

Anestetic [448]

Answer:

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Step-by-step explanation:

We need to find the equation of the line that is parallel to x=6y-5 and that passes through (5,-3).

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Compare given equation with y=mx+b

we get: m=1/6

We know that parallel equations has equal slope.

Then slope of required line m=1/6

Now plug the given point (5,-3) and slope m=1/6 into point slope formula:

$y-y_1=m\left(x-x_1\right)$

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$y+3=\frac{1}{6}x-\frac{5}{6}$

$y=\frac{1}{6}x-\frac{5}{6}-3$

$y=\frac{1}{6}x-\frac{23}{6}$

Now we need to rewrite that equation in standard form. Ax+By=C.

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x-23=6y

x-6y=23

Hence final answer is $x-6y=23$

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