Quadrilateral PUMA has coordinates at P(-5,-2), U(-1,2), M(4,-3), A(0,-7) and it is transformed by (x+3,y-5). Determined the ima

Question

3 years ago

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ge of M

1 answer:

IgorLugansk [536] · Answer 1 · 2022-04-08T11:40:38+03:00

The image of M is (7 , -8)

Step-by-step explanation:

Let us revise some transformation

If the point (x , y) translated horizontally to the right by h units then its image is (x + h , y)
If the point (x , y) translated horizontally to the left by h units then its image is (x - h , y)
If the point (x , y) translated vertically up by k units then its image is (x , y + k)
If the point (x , y) translated vertically down by k units then its image is (x , y - k)

∵ The quadrilateral PUMA has coordinates at:

P (-5 , -2) , U (-1 , 2) , M (4 , -3) , A (0 , -7)

∵ It is transformed by (x + 3 , y - 5)

- That means the quadrilateral translated 3 units right and 5 units

down, then we add each x-coordinate by 3 and subtract 5 from

each y-coordinate

∵ The coordinates of point M are (4 , -3)

∴ The image of point M = (4 + 3 , -3 - 5)

∴ The image of point M = (7 , -8)

The image of M is (7 , -8)

Learn more:

You can learn more about transformation in brainly.com/question/5563823

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