Answer:
finance charge refund is $91.53
Step-by-step explanation:
given data
finance charge F = $476
time t = 12 month
no of payment n = 5
to find out
finance charge refund
solution
we will apply here finance charge refund formula that is
finance charge refund = F ×
put here value we get
finance charge refund = 476 ×
finance charge refund = 476 ×
finance charge refund = 476 ×
finance charge refund = 476 × 0.1923
finance charge refund = 91.53
so finance charge refund is $91.53
Answer:
The values for expression is h = - 2 and k = 5
Step-by-step explanation:
Given algebraic expression can be written as :
2 x³ - 10 x² + 11 x - 7 = ( x - 4 ) × ( 2 x² + h x + 3 ) + k
Now opening the bracket
Or, 2 x³ - 10 x² + 11 x - 7 = x × ( 2 x² + h x + 3 ) - 4 × ( 2 x² + h x + 3 ) + k
Or, 2 x³ - 10 x² + 11 x - 7 = 2 x³ + h x² + 3 x - 2 x² - 4 h x - 12 +k
Or , 2 x³ - 10 x² + 11 x - 7 = 2 x³ + ( h - 2 ) x² + ( 3 - 4 h ) x - 12 + k
Now, equating the equation both sides
I.e - 10 = ( h - 2 )
Or , h - 2 = - 10
I.e , h = - 10 + 2
∴ h = - 2
Again , 11 = ( 3 - 4 h )
or, 11 = 3 - 4 h
or, 11 - 3 = - 4 h
or, 8 = - 4 h
∴ h =
I.e h = - 2
Again
- 7 = - 12 + k
Or, k = - 7 + 12
∴ k = 5
Hence The values for expression is h = - 2 and k = 5 . Answer
Answer: 91
Step-by-step explanation:
Given : The number of documentaries = 5
The number of comedies = 7
The number of mysteries = 4
The number of horror films =5
The total number of movies other than comedy = 14
Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-
Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .