The answer is true. An altitude of a triangle is the perpendicular segment from a vertex to the line containing the opposite side.
√896z^15/<span>√225z^6
= </span>√896z^9/<span>√225
= </span>√64√14(z^4)<span>√z/15
= 8</span>√14(z^4)<span>√z/15
= (8z^4/15) * </span><span>√14z
x = 8</span>
We know that
∠ TSR = 84°
if SQ bisects ∠ <span>TSR
then
</span>∠ RSQ = ∠ TSR/2
<span>so
</span>∠ RSQ = (1/2)*84°----- 42°
∠ RSQ = 3x-9
3x-9=42-------> 3x=42+9------> 3x=51-----> x=51/3-----> x=17°
<span>
the answer is
</span>x=17°<span>
</span>
Answer:
799
Step-by-step explanation:
Let x = the hundreds digit
Let y = the ones digit
x = y-2
We want to maximize x and y. The both have to be single digit numbers
Rewriting this
x+2 =y
The largest x can be is 7 if y is a single digit
x is 7 and y is 9
We can pick the tens digit. Make it as big as possible to make out number as large as possible
799
Answer:
1 2/6 3 3/4
Step-by-step explanation:
