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katrin2010 [14]
3 years ago
9

The table represents the cost for oranges in Mr. Nguyen's store. Image In this situation, cost is a function of the number of or

anges. Which set represents the domain of this function?
Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0

Answer:

USE SOCRACTIC IT WOULD REALLY HELP

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Help me with this question <br>I will mark brainlist <br>no web link <br><br>Solve :-<br>9n²-64=0​
Archy [21]
Factorize

(3n + 8) (3n - 8) = 0
3n + 8 = 0 and 3n - 8 = 0

Solve both for n

3n + 8 = 0
3n = -8
n = -8/3


3n - 8 = 0
3n = 8
n = 8/3

Therefore n = -8/3 and n = 8/3
6 0
2 years ago
Which on is it? need asap Thank you !!!
skad [1K]

Irrational number has unsolvable root overs.

Last two are now our options

\\ \bull\tt\dashrightarrow \sqrt{25}=5

Hence its not irrotational.

Hence

Option C is irrational.

6 0
3 years ago
Round 1.7802 to 1 significant figure
tiny-mole [99]

Answer:

It would be 2

Step-by-step explanation:

Since they are looking for only 1 significant fig. you would round the number that would make this correct, for example:

You would look at 1.7 and ignore the others...

7 is greater than 5 so it'll affect the 1

And that how you get 2 : )

3 0
2 years ago
Betty likes to skate at a skate park that is due south of her school and due west of her
AURORKA [14]
The answer will be 12+13 because the skatepark is 12km from school and her favorite game store was 13 km so it’s 12+13=25km
6 0
3 years ago
Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1
WITCHER [35]

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

4 0
2 years ago
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