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2 years ago

Transform the equation formulated into standard form ax²+bx+c=0

Mathematics

1 answer:

nekit [7.7K]2 years ago

8 0

Answer:

ax^2 + bx + c = 0

Here is a specific example:

5x^2 - 3x + 2 = 0

In other words:

You have zero on the right.

On the left, you have the powers of “x” in descending order.

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How do I even start this? And how to i order the equation to solve

Kobotan [32]

$f(g(h(x)))=f(g(\sqrt x))=f(\sqrt x-1)=\boxed{(\sqrt x-1)^4+4}$

This is because

$h(x)=\sqrt x$

$g(x)=x-1$

$\implies g(h(x))=\sqrt x-1$

(that is, replace any instance of x in the definition of g with √x )

and

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(replace any x in f with √x - 1)

Also acceptable:

$(\sqrt x-1)^4+4=((\sqrt x)^4-4(\sqrt x)^3+6(\sqrt x)^2-4\sqrt x+1)+4$

$=\boxed{x^2-4x\sqrt x+6x-4\sqrt x+5}$

(assuming x is not negative)

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3 years ago

Transform the equation formulated into standard form ax²+bx+c=0​

Transform the equation formulated into standard form ax²+bx+c=0