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Dafna1 [17]
3 years ago
7

If f(x) = 3x + 1 and g(x) = 5x - 1 Solve for f/g.

Mathematics
1 answer:
goldenfox [79]3 years ago
4 0
f(x)=3x+1;\ g(x)=5x-1\\\\\left(\dfrac{f}{g}\right)(x)=\dfrac{3x+1}{5x-1}
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What is the greatest common factor you can use to divide the numerator and denominator of the fraction 28/32?
Anastaziya [24]
The greatest common factor is 4.

28/32 / 4 = 7/8
7 0
3 years ago
Find the infinite geometric sum of 80 + 10 +1.25 + ... to 5 decimal places past the decimal point.
SIZIF [17.4K]

first term.

a= 80

second term. a2=10

so Common ratio r=a2/a =10/80=1/8=0.125

checking for the validity of common ratio.

a2×r=10×1/8=10×0.125=1.25 =a3= Third term.

Hence it is true.

Now 4th Term =1.25/8=0.15625

It can be observed that 4TH term Has digit that is 5 places past the decimal point.

Hence, 0.15625 is the terminating number as per the question.

So the required sum is.

S=a+a2+a3+a4

->S=80+10+1.25+0.15625

->S= 91.40625

Hope it helps...

Regards,

Leukonov/Olegion.

7 0
4 years ago
Solve for x <br> 3x+4 = (2/5)x +2
julsineya [31]

Answer:-10/13

Step-by-step explanation:

3x+4 = (2/5)x + 2

First move the 4 to the other side by subtracting it.

it becomes : 3x = (2/5)x - 2

then multiply everything by 5 to get rid of the fraction.

it becomes 15x = 2x -10

then move the 2x to the other side by subtracting it.

you get 13x = -10

now you can divide everything by 13 to isolate the x.

and you get x = -10/13

3 0
3 years ago
Read 2 more answers
The graph shows point F located at (0, 6) and line d given by the equation y = 0.
Alex_Xolod [135]

Answer:

equidistant from point F and line d: (0, 3); (6, 6) and (-6, 6)

not equidistant from point F and line d: (3, 0); (3, 5) and (-2, 2)

Step-by-step explanation:

Point (0, 3)

Distance from point (0, 6) = 3

Distance from line d = 3

Point (6, 6)

Distance from point (0, 6) = 6

Distance from line d = 6

Point (3, 0)

Distance from point (0, 6) = √[(3 - 0)² + (0 - 6)²] = √45

Distance from line d = 0

Point (3, 5)

Distance from point (0, 6) = √[(3 - 0)² + (5 - 6)²] = √10

Distance from line d = 5

Point (-2, 2)

Distance from point (0, 6) = √[(-2 - 0)² + (2 - 6)²] = √20

Distance from line d = 2

Point (-6, 6)

Distance from point (0, 6) = 6

Distance from line d = 6

8 0
3 years ago
Find the area_______​
Ray Of Light [21]

Answer:

32√3

Step-by-step explanation:

area = product of diagonals/2

= (8√3 × 8)/2

= 64√3 /2

= 32√3

6 0
3 years ago
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