The greatest common factor is 4.
28/32 / 4 = 7/8
first term.
a= 80
second term. a2=10
so Common ratio r=a2/a =10/80=1/8=0.125
checking for the validity of common ratio.
a2×r=10×1/8=10×0.125=1.25 =a3= Third term.
Hence it is true.
Now 4th Term =1.25/8=0.15625
It can be observed that 4TH term Has digit that is 5 places past the decimal point.
Hence, 0.15625 is the terminating number as per the question.
So the required sum is.
S=a+a2+a3+a4
->S=80+10+1.25+0.15625
->S= 91.40625
Hope it helps...
Regards,
Leukonov/Olegion.
Answer:-10/13
Step-by-step explanation:
3x+4 = (2/5)x + 2
First move the 4 to the other side by subtracting it.
it becomes : 3x = (2/5)x - 2
then multiply everything by 5 to get rid of the fraction.
it becomes 15x = 2x -10
then move the 2x to the other side by subtracting it.
you get 13x = -10
now you can divide everything by 13 to isolate the x.
and you get x = -10/13
Answer:
equidistant from point F and line d: (0, 3); (6, 6) and (-6, 6)
not equidistant from point F and line d: (3, 0); (3, 5) and (-2, 2)
Step-by-step explanation:
Point (0, 3)
Distance from point (0, 6) = 3
Distance from line d = 3
Point (6, 6)
Distance from point (0, 6) = 6
Distance from line d = 6
Point (3, 0)
Distance from point (0, 6) = √[(3 - 0)² + (0 - 6)²] = √45
Distance from line d = 0
Point (3, 5)
Distance from point (0, 6) = √[(3 - 0)² + (5 - 6)²] = √10
Distance from line d = 5
Point (-2, 2)
Distance from point (0, 6) = √[(-2 - 0)² + (2 - 6)²] = √20
Distance from line d = 2
Point (-6, 6)
Distance from point (0, 6) = 6
Distance from line d = 6
Answer:
32√3
Step-by-step explanation:
area = product of diagonals/2
= (8√3 × 8)/2
= 64√3 /2
= 32√3