Determine the 28th term of the sequence -242, -251, -260
1 answer:
We can figure this out using the explicit formula.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
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Answer:
37.59 nautical miles
Explanation:
Distance = Speed x Time
The speed of the first ship = 12 knots
Thus, the distance covered after 1.5 hours
The speed of the second ship = 22 knots
Thus, the distance covered after 1.5 hours
The diagram representing the ship's path is drawn and attached below:
The angle at port = 90 degrees.
The triangle is a right triangle.
Using Pythagorean Theorem:
The two ships are 37.59 nautical miles apart after 1.5 hours.
