Question

Determine the 28th term of the sequence -242, -251, -260

Answer 1

We can figure this out using the explicit formula.
$f(n)=f(1)+d(n-1)$
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.

f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n

Now, we can input 28 for n and solve.

f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485

The 28th term of the sequence is -485.