Determine the 28th term of the sequence -242, -251, -260
1 answer:
We can figure this out using the explicit formula.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
n represents the term we are looking for.f(1) represents the first term in the sequence, which in this case, is -242.d represents the common difference, which in this case, is -9.
f(n) = -242 + -9(n - 1)
f(n) = -242 - 9n + 9
f(n) = -233 - 9n
Now, we can input 28 for n and solve.
f(28) = -233 - 9(28)
f(28) = -233 - 252
f(28) = -485
The 28th term of the sequence is -485.
You might be interested in
In any trapezoid, the area is given by
where B and b are the two bases, and h is the height. You're given all these elements already, so you only need to plug the values in:
