Question

On New​ Year's Eve, the probability of a person driving while intoxicated or having an accident is 0.37. If the probability of driving while intoxicated is 0.32 and the probability of having a driving accident is 0.12​, find the probability of a person having a driving accident while intoxicated

Answer 1

Answer:

The probability of a person having a driving accident while intoxicated is 0.07

Step-by-step explanation:

Hi, well, let´s put this on a formula, I think it is the best way to explain it.

$P(A+I)=P(A)+P(I)-P(AorI)$

Where:

P(A+I) = Probability of having a driving accident while intoxicated.

P(A) = Probability of a person of having an accident.

P(I) = Probablity person being intoxicated.

P(A or I) = Probability of a person for being intoxicated or having an accident.

Therefore, things should look like this:

$P(A+I)=0.12+0.32-0.37=0.07$

So, the  probability of a person having a driving accident while intoxicated is 0.07.

Best of luck.