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3 years ago

Witch best describes the storage of the genetic code

Chemistry

1 answer:

natulia [17]3 years ago

5 0

Answer:

The genetic code is stored in the DNA. DNA is a molecule formed by a sugar, deoxyribose, a phosphate group and four combined nitrogen bases: Adenine (A), Thymine (T), Cytosine (C) and Guanine (G). A gene is a part of DNA.

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Convert 685K to Fahrenheit

joja [24]

773.33 degrees F
F=Fahrenheit
K=Kelvin
F=K x 9/5 - 459.67
773.33 = 685 x 9/5 - 459.67

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3 years ago

Isaac Newton’s investigations of gravity explained which truth?

umka2103 [35]

<span>C. Gravity acts on all objects in the universe.
think about Newtons Laws of Motion</span>

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2 years ago

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A forensic scientist reports that a dead woman had high concentrations of a pain-fighting drug in her blood. What type of analys

AlladinOne [14]

C) the scientist made an identification by identifying the amount of drug in her blood and realising it was high

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2 years ago

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Which of the following tools is not used for measurement?

Verdich [7]

Answer:

tape measure

Explanation:

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2 years ago

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago