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Tcecarenko [31]
3 years ago
8

In neutron moderation, neutrons are slowed down so that:

Chemistry
1 answer:
erastovalidia [21]3 years ago
6 0

B. Nuclear fission reactions are slowed down as well.

Neutron moderation is a substance which slows down neutron. In some reaction moderator is same as coolant.

This is also used to slow down nuclear fission reaction and continue chain reactions.

The collision between neutron and nuclei is more elastic and more neutrons will be slowed due to size of the neutron.

Learn more at brainly.com/question/24371385

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The equilibrium constant is equal to 5.00 at 1300 K for the reaction:2 SO2(g) + O2(g) ⇌ 2 SO3(g). If initial concentrations are
oee [108]

This is an incomplete question, here is a complete question.

The equilibrium constant is equal to 5.00 at 1300 K for the reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

If initial concentrations are [SO₂] = 1.20 M, [O₂] = 0.45 M, and [SO₃] = 1.80 M, the system is

A) at equilibrium.

B) not at equilibrium and will remain in an unequilibrated state.

C) not at equilibrium and will shift to the left to achieve an equilibrium state.

D) not at equilibrium and will shift to the right to achieve an equilibrium state.

Answer : The correct option is, (A) at equilibrium.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The expression for reaction quotient will be :

Q=\frac{[SO_3]^2}{[SO_2]^2[O_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

Now put all the given values in this expression, we get

Q=\frac{(1.80)^2}{(1.20)^2\times (0.45)}=5.0

The given equilibrium constant value is, K_c=5.00

Equilibrium constant : It is defined as the equilibrium constant. It is defined as the ratio of concentration of products to the concentration of reactants.

There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q=K_c that means product = reactant. So, the reaction is in equilibrium.

Hence, the correct option is, (A) at equilibrium.

7 0
3 years ago
A scientist is measuring the pressure that is exerted by each of the following gases in the atmosphere: carbon dioxide,
Pani-rosa [81]

Answer:

D. Partial pressure

Explanation:

Partial pressure is the individual pressure exerted by each gas present in a gaseous mixture. As he is measuring the pressure of each gas in the atmosphere separately, so PARTIAL PRESSURE is the exact term for his measurement.

8 0
3 years ago
What is an orbital?
Alika [10]
Is a mathematical function describing the location and wave
4 0
3 years ago
The following equations are half reactions and reduction potentials. Ag+ (aq) + e– Ag(s) has a reduction potential of +0.80 V. C
Lady bird [3.3K]

Answer : The correct option is, (A) silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.

Explanation :

The given half reaction are :

1st half reaction : Ag^+(aq)+e^-\rightarrow Ag(s)

The reduction potential of this reaction = +0.80 V

2nd half reaction : Cr^{3}+(aq)+3e^-\rightarrow Cr(s)

The reduction potential of this reaction = -0.74 V

From the reduction potentials, we conclude that the reaction which have positive reduction potential, they will gain electrons more easily and reduced itself and act as a stronger oxidizing agent.

Or we can say that the reaction which have negative reduction potential, they will lose electrons more easily and oxidized itself and act as a stronger reducing agent.

The reduction potential of 1st half reaction is positive and 2nd half reaction is negative.

Therefore, the silver ion gains electrons more easily and is a stronger oxidizing agent than a chromium(III) ion.


5 0
4 years ago
Read 2 more answers
In the reaction Mg (s) + 2HCl (aq) -> H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 300 millilite
d1i1m1o1n [39]
Mg(s) + 2HCl(aq) = H₂(g) + MgCl₂(aq)

v=300 ml=0.3 l
c=4 mol/l

n(HCl)=vc

m(H₂)/M(H₂)=n(HCl)/2

m(H₂)=M(H₂)vc/2

m(H₂)=2.0g/mol·0.3 l · 4mol/l /2 = 1.2 g

1.2 grams of hydrogen gas will be produced
5 0
4 years ago
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